Solved

How to get one record from a range in an sql view based on the value of a field in another table

Posted on 2013-12-20
4
392 Views
Last Modified: 2013-12-22
Hi there:

I have an Employees table with the fields called EmployeeName and YearsOfService. I have another table called Bonus that contains the fields: MinimumYears and BonusAmt. I want to create a view that displays the EmployeeName, YearsOfService and BonusAmt (one record per employee).

The Bonus table has the values:
MinimumYears | Bonus
0 | 0
2 | 1000
4 | 2800
6 | 4000

Two records in the Employees table may read:
EmployeeName | YearsOfService
Barry Blue | 2.65
Wayne Brown | 4.80
Greg White |1.94

The final view should read:
EmployeeName | YearsOfService | BonusAmt
Barry Blue | 2.65 | 1000
Wayne Brown | 4.80 | 2800
Greg White |1.94 | 0

So, what would be the SQL statement to get the required results?
0
Comment
Question by:Rivess
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 2
4 Comments
 
LVL 13

Accepted Solution

by:
sameer2010 earned 500 total points
ID: 39733306
Try this
-- If you want view, then only include create view
create view bonusview as 
select a.EmployeeName,a.YearsOfService,(select max(b.bonus) from Bonus_Table b where b.MinimumYears < a.YearsOfService) BonusAmt 
from Employees_Table a

Open in new window

0
 
LVL 16

Expert Comment

by:Easwaran Paramasivam
ID: 39733500
You could use below one as well.

create view bonusview as 

select
e.EmployeeName,e.YearsOfService, b.bonus
from
Employees_Table e
inner join  Bonus_Table  b on b.MinimumYears =  Floor(e.YearsOfService)

Open in new window

0
 

Author Closing Comment

by:Rivess
ID: 39735235
A simple and tricky piece of code.
0
 

Author Comment

by:Rivess
ID: 39735240
The second solution requires an entry for each possible year in the Bonus table. In the current setup an employee with 3 years won't get any bonus at all since the 'Floor(X)' is trying to match a 3 in the bonus table and an entry with 3 years does not exist. Thanks for your prompt reply.
0

Featured Post

Online Training Solution

Drastically shorten your training time with WalkMe's advanced online training solution that Guides your trainees to action. Forget about retraining and skyrocket knowledge retention rates.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

INTRODUCTION: While tying your database objects into builds and your enterprise source control system takes a third-party product (like Visual Studio Database Edition or Red-Gate's SQL Source Control), you can achieve some protection using a sing…
Occasionally there is a need to clean table columns, especially if you have inherited legacy data. There are obviously many ways to accomplish that, including elaborate UPDATE queries with anywhere from one to numerous REPLACE functions (even within…
Monitoring a network: why having a policy is the best policy? Michael Kulchisky, MCSE, MCSA, MCP, VTSP, VSP, CCSP outlines the enormous benefits of having a policy-based approach when monitoring medium and large networks. Software utilized in this v…
Michael from AdRem Software explains how to view the most utilized and worst performing nodes in your network, by accessing the Top Charts view in NetCrunch network monitor (https://www.adremsoft.com/). Top Charts is a view in which you can set seve…

707 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question