Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people, just like you, are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
Solved

Compare query where ID's are different

Posted on 2013-12-21
2
255 Views
Last Modified: 2013-12-21
Hi,

I need help with this query. It is to compare pre conversion data to post conversion data. recno = roid + 2000 (meaning that we added 2000 to the roid so the id's would not hit existing records in the target table.

Here is what I have so far:
SELECT
	`tpsmotorsports source`.`orders money`.recno AS recno,
	`tpsmotorsports target`.ledger.roid,        -- is recno + 2000
	`tpsmotorsports source`.`orders money`.taxamt,
	`tpsmotorsports target`.ledger.amount,
	`tpsmotorsports target`.ledger.transactiontype
FROM
	`tpsmotorsports source`.`orders money`
LEFT JOIN `tpsmotorsports target`.ledger ON `tpsmotorsports source`.`orders money`.recno = `tpsmotorsports target`.ledger.roid
WHERE
	transactiontype = 'RO - Taxes Owed'

Open in new window


For this to work I need to have the join factor in the 2000 increase in the roid value. For example recno 1 will be roid 2001. I am not clear on how to do this and what I have tried has failed. Any idea how to make this work?

Thanks,
c
0
Comment
Question by:ckelsoe
2 Comments
 
LVL 8

Accepted Solution

by:
vr6r earned 500 total points
ID: 39734146
Have you tried just including the calculation in the join?  Either subtracting 2000 from the roid or adding 2000 to the recno?
Something like this:
LEFT JOIN `tpsmotorsports target`.ledger ON `tpsmotorsports source`.`orders money`.recno = (`tpsmotorsports target`.ledger.roid - 2000)

Open in new window

0
 

Author Comment

by:ckelsoe
ID: 39734154
I did and it returns 0 records. Then I realized I had added 2000 instead of subtract 2000. Another ID10t problem I think.

Thanks for the help!
0

Featured Post

Announcing the Most Valuable Experts of 2016

MVEs are more concerned with the satisfaction of those they help than with the considerable points they can earn. They are the types of people you feel privileged to call colleagues. Join us in honoring this amazing group of Experts.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
Mysql Left Join Case 10 70
MySQL Sub-Select Query Returning Duplicate Result 7 45
Need help with a Stored Proc on Sql Server 2012 4 28
Very Large data in MYSQL 7 73
Confronted with some SQL you don't know can be a daunting task. It can be even more daunting if that SQL carries some of the old secret codes used in the Ye Olde query syntax, such as: (+)     as used in Oracle;     *=     =*    as used in Sybase …
Does the idea of dealing with bits scare or confuse you? Does it seem like a waste of time in an age where we all have terabytes of storage? If so, you're missing out on one of the core tools in every professional programmer's toolbox. Learn how to …
This video shows how to quickly and easily add an email signature for all users on Exchange 2016. The resulting signature is applied on a server level by Exchange Online. The email signature template has been downloaded from: www.mail-signatures…

829 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question