Spring context config initialization error

I am getting the following error shown below upon spring  context configuration file initialization, any help would be appreciated.

ServletWrappe E   SRVE0100E: Did not realize  init() exception thrown by servlet abc-ws: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'efgWebServiceTemplate' defined in ServletContext resource [/WEB-INF/efgSpringContext.xml]: Error setting property values; nested exception is org.springframework.beans.NotWritablePropertyException: Invalid property 'interceptors' of bean class [org.springframework.ws.client.core.WebServiceTemplate]: Bean property 'interceptors' is not writable or has an invalid setter method. Does the parameter type of the setter match the return type of the getter?

I created a new web service that get called from within an exising web service.

The exisitng web service interceptor is configured as in the following:

<bean id="abcSecurityTokenInterceptor" class="com.pnc.ecommerce.util.spring.ws.security.SecurityTokenInterceptor">
<property name="verifySecurityHandler" ref="abcVerifySecurityHandler" />
<property name="timestampTokenHandler" ref="abcTimestampTokenHandler" />
</bean>

<bean class="org.springframework.ws.server.endpoint.mapping.PayloadRootQNameEndpointMapping">
   <property name="mappings">
       <props>
……………….
……………….
………………
       </props>
   </property>
   <property name="interceptors">
      <list>
      <ref bean="abcSecurityTokenInterceptor"/>
      </list>
   </property>
</bean>

The new web service (which is called from within the existing  web service) has an interceptor that is configured as in the following:

<bean id="efgSecurityInterceptor"
 class="org.springframework.ws.soap.security.wss4j.Wss4jSecurityInterceptor">
<property name="securementActions" value="UsernameToken"/>
<property name="securementPasswordType" value="PasswordText"/>
</bean>

<bean id="efgWebServiceTemplate"
 class="org.springframework.ws.client.core.WebServiceTemplate">
<property name="messageFactory">
<bean
class="org.springframework.ws.soap.saaj.SaajSoapMessageFactory" />
</property>

<property name="marshaller" ref="efgMarshaller"/>
<property name="unmarshaller" ref="efgMarshaller"/>
<property name="interceptors">
<list>
<ref local="efgSecurityInterceptor" />
</list>
</property>
</bean>

Web.xml has the following:

<display-name>
ABCWebApp
</display-name>
<servlet>
<servlet-name>abc-ws</servlet-name>
<servlet-class>
org.springframework.ws.transport.http.MessageDispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>
classpath:abc-ws-servlet.xml
/WEB-INF/efgSpringContext.xml
</param-value>
</init-param>
<load-on-startup>2</load-on-startup>
</servlet>


Thanks
Jeff
jeffreyjseamanAsked:
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jeffreyjseamanConnect With a Mentor Author Commented:
When I comment out the interceptor, the context get loaded fine but then there will be no security applied to the client and then it will fail when the client make the call. :


       
      <!-- Seurity Interceptor -->
      <bean id="efgSecurityInterceptor"
              class="org.springframework.ws.soap.security.wss4j.Wss4jSecurityInterceptor">
            <property name="securementActions" value="UsernameToken"/>
            <property name="securementPasswordType" value="PasswordText"/>
      </bean>      

      <!-- WebServiceTemplate -->
      <bean id="efgWebServiceTemplate"
              class="org.springframework.ws.client.core.WebServiceTemplate">
            <property name="messageFactory">
                  <bean
                        class="org.springframework.ws.soap.saaj.SaajSoapMessageFactory" />
            </property>

            <property name="marshaller" ref="queryCustomerStatusMarshaller"/>
            <property name="unmarshaller" ref="queryCustomerStatusMarshaller"/>
            <!--<property name="interceptors">
                  <list>
                        <ref local="efgSecurityInterceptor" />
                  </list>
            </property> -->
      </bean>
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mccarlIT Business Systems Analyst / Software DeveloperCommented:
What version of Spring WS are you using? And what version of Spring (ie. the core, beans, context, etc)?
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jeffreyjseamanAuthor Commented:
I am using:  spring-ws-core-1.5.6.jar  Please see below.

Class-Path:
 lib/XMLStreamException.jar
 lib/jaxen-1.1.1.jar
 lib/jdom-1.1.jar
 lib/log4j-1.2.15.jar
 lib/saaj-api.jar
 lib/saaj-impl.jar
 lib/spring-2.0.8.jar
 lib/wsdl4j-1.6.1.jar
 lib/Phaos_Crypto.jar
 lib/Phaos_Security_Engine.jar
 lib/SmdClientJavaApp.jar
 lib/bcprov-jdk15-136.jar
 lib/smd-schemas.jar
 lib/spring-oxm-1.0.0.jar
 lib/spring-ws-core-1.5.6.jar
 lib/spring-ws-core-tiger-1.5.6.jar
 lib/spring-oxm-tiger-1.5.6.jar
 lib/spring-ws-security-1.5.6.jar
 lib/spring-xml-1.5.6.jar
 lib/stax-api-1.0.1.jar
 lib/wss4j-1.5.6.jar
 lib/xbean.jar
 lib/commons-codec-1.3.jar
 lib/jaxb-2.1-20090206/jaxb-api.jar
 lib/jaxb-2.1-20090206/jaxb-impl.jar
 lib/xmlsec-1.4.2.jar
 lib/wsp_cus_status-jaxb-1.0.jar

In the context xml file I have the following:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
      xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd">


I wanted to mention that I don't see the issue when I run in local (using RAD / WAS 6.1), but the initialization fails in the QA environment.
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jeffreyjseamanAuthor Commented:
nobody else gave any answers and it was resolved by myself
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