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Junk character in assigning int to char data type why?
void main()
{
int a=5;
char str[0];
str[0]=a;
cout<<str[0];
}
Doesn't print 5, why.
{
int a=5;
char str[0];
str[0]=a;
cout<<str[0];
}
Doesn't print 5, why.
Dave Baldwin
Because you have assigned a binary 5 to str[0] and not the character '5'. If you make the first assignment char a = '5'; then it should print '5'.
In declaring
str[0]=a;
you are saying input the character with the ASCII value of 5
If you use int
a='5';
and ouput a you will get 53 as ascii value of 5
Have a look at this ASCII table
http://www.cs.cmu.edu/~pattis/15-1XX/common/handouts/ascii.html
Michael
str[0]=a;
you are saying input the character with the ASCII value of 5
If you use int
a='5';
and ouput a you will get 53 as ascii value of 5
Have a look at this ASCII table
http://www.cs.cmu.edu/~pattis/15-1XX/common/handouts/ascii.html
Michael
ASKER
I an writing a code which converts aaa to a3
Simlarly aaabbbbb as a3b5
This is why i need 5 to be appended in char array.
Simlarly aaabbbbb as a3b5
This is why i need 5 to be appended in char array.
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ASKER
What is the logic behind.
It works by adding the ASCII value of char '0' to the integer digit.