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remove whitespace from hash_ref

Posted on 2013-12-27
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Last Modified: 2013-12-27
I have hash is formatted like this
params => {test =>  ' 5 ' }

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my goal is to strip any white space from the value of the test key.  What I have is not working of course.  How can I accomplish this in a 1 liner?  Thanks

$params->{$trim_filter->{$_}} = delete $params->{$_} foreach keys %$params;

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#set the trim_filter
my $trim_filter = sub {
    return scalar($_[0] =~ s/^\s+|\s+$//g)
};

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Question by:hexfusion
2 Comments
 
LVL 85

Accepted Solution

by:
ozo earned 2000 total points
ID: 39742869
#assuming you meant
$params = {test =>  ' 5 ' };

s/^\s+//,s/\s+$// for values %$params;
# or
$trim_filter->($_) for values %$params;


#if you meant
$params = {'  test   ' =>  5 };
#then you could use
$trim_filter = sub { $_[0] =~ s/^\s+|\s+$//g; return $_[0] }
#to do
$params->{$trim_filter->($_)} = delete $params->{$_} foreach keys %$params;
0
 
LVL 2

Author Closing Comment

by:hexfusion
ID: 39742989
Thanks as always ozo
0

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