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SQL Server Computed Column Specification for Age

Posted on 2014-01-02
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Can anyone see my syntax error?

I get following message: Error validating the formula for column 'Age'.

(case when dayofyear([BirthDate]) < dayofyear(getdate()) then datediff(year,[BirthDate],getdate())-1 else  datediff(year,[BirthDate],getdate()) end)

Thanks,
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Question by:CloudApps
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dsacker earned 2000 total points
ID: 39751765
DayOfYear is not a function (unless you wrote one). Use this definition for your computed column:

CASE
    WHEN DATEPART(dayofyear, BirthDate) < DATEPART(dayofyear, GETDATE())
         THEN DATEDIFF(YEAR, BirthDate, GETDATE()) - 1
    ELSE DATEDIFF(YEAR, BirthDate, GETDATE())
END

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I separated it out for readability (and to verify it worked). Return it to one line or however you wish to lower-case it.
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by:sammySeltzer
ID: 39751777
select DATEDIFF(dayofyear, BirthDate, getdate()) -1 

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Expert Comment

by:Guy Hengel [angelIII / a3]
ID: 39751782
I presume dayofyear is a customer function, in which case you have to prefix it with the functions' owner name:

dbo.dayofyear(...)
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by:sammySeltzer
ID: 39751815
Is dayofyear a sql server 2012 function - a new feature in sql server?
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by:Kevin Cross
ID: 39751908
You may find this thread helpful:
http://www.experts-exchange.com/Microsoft/Development/MS-SQL-Server/SQL-Server-2005/Q_23808219.html

Scott's approach is similar to dsacker's above, except he eliminated the repetition of the DATEDIFF by putting the CASE on the subtraction.

In other words, you can do this:
DATEDIFF(YEAR, BirthDate, GETDATE()) - CASE WHEN DATEPART(dayofyear, BirthDate) < DATEPART(dayofyear, GETDATE()) THEN  1 ELSE 0 END
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Author Closing Comment

by:CloudApps
ID: 39751963
dsacker,

Thanks for figuring out what I was trying to accomplish. Your syntax worked to solve the problem.

Sorry, to very one else for the poor presentation of my problem.
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