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ASP/VB script page - SP help

Posted on 2014-01-02
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Last Modified: 2014-01-02
I am using ASP/VB script and MS SQL 2008

There is a SP in my page that inserts data in my DB.

---

Dim SPInsertPassword__Password
SPInsertPassword__Password = "0"
if(EncrytPswd("demo") <> "") then SPInsertPassword__Password = EncrytPswd("demo")

----

The above will insert the word "demo" into a database field, when it is inserted it is also enctrypted.  That is what the "Encrypt" part is for, so far so good.

I have to replace the word "demo" for a random password.  I already have the script below to generate a random password. What I need help with is to save the random password in a variable and then use it to insert it instead of the word 'demo' using the code above.

This is my script:

<script language="vbscript" runat="server">

Sub StrRandomize(strSeed)
        Dim i, nSeed
        nSeed = CLng(0)
        For i = 1 To Len(strSeed)
                nSeed = nSeed Xor ((256 * ((i - 1) Mod 4) * AscB(Mid(strSeed, i, 1))))
        Next
        'Randomiser
        Randomize nSeed
End Sub
'--GeneratePassword(nLength)
'--Generates friendly passwords for remembering and pronounciation
Function GeneratePassword(nLength)
        Dim i, bMadeConsonant, c, nRnd
            'You may adjust the below constants to include local,
            'eg. scandinavian characters. This way your passwords
            'will not be limited to latin characters.
        Const strDoubleConsonants = "bdfglmnpst"
        Const strConsonants = "bcdfghklmnpqrstv"
        Const strVocal = "aeiou"
        GeneratePassword = ""
        bMadeConsonant = False
        For i = 0 To nLength
                'Get a random number number between 0 and 1
                nRnd = Rnd
                'Simple or double consonant, or a new vocal?
                'Does not start with a double consonant
                        '15% or less chance for the next letter being a double consonant
                If GeneratePassword <> "" AND (bMadeConsonant <> True) AND (nRnd < 0.15) Then
                        'double consonant
                        c = Mid(strDoubleConsonants, Int(Len(strDoubleConsonants) * Rnd + 1), 1)
                                    'response.write int(Len(strDoubleConsonants) * Rnd + 1)
                                    'response.write "<br>"
                        c = c & c
                                    i = i + 1
                        bMadeConsonant = True
                Else
                                    '80% or less chance for the next letter being a consonant,
                                    'depending on wether the last letter was a consonant or not.
                        If (bMadeConsonant <> True) And (nRnd < 0.95) Then
                                'Simple consonant
                                c = Mid(strConsonants, Int(Len(strConsonants) * Rnd + 1), 1)
                                bMadeConsonant = True
                                    '5% or more chance for the next letter being a vocal. 100% if last
                                    'letter was a consonant - theoreticaly speaking...
                        Else
                                'If last one was a consonant, make vocal
                                c = Mid(strVocal,Int(Len(strVocal) * Rnd + 1), 1)
                                bMadeConsonant = False
                        End If
                End If
                'Add letter
                GeneratePassword = GeneratePassword & c
        Next
        'Is the password long enough, or perhaps too long?
        If Len(GeneratePassword) > nLength Then
                GeneratePassword = Left(GeneratePassword, nLength)
        End If
End Function

StrRandomize CStr(Now) & CStr(Rnd)

</script>
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Question by:Aleks
  • 3
4 Comments
 
LVL 34

Accepted Solution

by:
Big Monty earned 2000 total points
ID: 39752732
to put the newly created 10 char password into a variable, just do:

SPInsertPassword__Password = EncrytPswd( GeneratePassword( 10 ) )

do you also need help saving it?
0
 

Author Comment

by:Aleks
ID: 39752750
let me try the above first.
0
 

Author Comment

by:Aleks
ID: 39752759
Great, thanks !
0
 

Author Closing Comment

by:Aleks
ID: 39752760
:)
0

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