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If the condition is true it will continue on the very next line. If false it would continue after the &quot;end if&quot; following the If(condition) statement.
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Logically (LOL) it should go to line 5 if the condition on line 4 = true. If the condition = false it should return to line 3 until it exhausts the number of inputs available to that line. <br />
<br />
For example lets say line 3 is actually:<br />
<br />
for a=1 to 10<br />
<br />
A condition of false on line 4 will return to line 3 until a = 11, without processing line 5 at which point it will return to line 2 and start the process all over again. If the condition is true it wil process line 5 and return to line 3 until a = 11. That is how the code is currently shown. &nbsp;That may not be reality though since you don't show the rest of the code after line 5.<br />
<br />
This description is based on the following assumed code:<br />
<br />

<pre><code class="code-1 nolinks" id="code-20-39765657-1"><span>for {</span>
<span>   for {</span>
<span>     for a = 1 to 10{</span>
<span>       if(condition) continue;</span>
<span>       some_variable = some_expression   </span>
<span>      }</span>
<span>   }</span>
<span>}</span>
</code></pre>
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sodea63 and pony10us,<br />
<br />
You're both missing the &quot;continue&quot; statement at the end of line 4. If the condition is true, the next line that will be executed is line 3, not line 5.<br />
<br />
Ken Butters' answer is correct.
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CPColin,<br />
<br />
You are correct. I was looking at the &quot;continue&quot; incorrectly as I was working on several things here at work at the same time. &nbsp;<br />
<br />
The logic (there's that word again) in my explanation is backwards for the results of the condition on line 4. The &quot;continue&quot; is an actual statement in the code and therefore evaluates as: <br />
<br />
If condition evaluates to true return to the for/while/etc. loop otherwise go on with the next line of code. <br />
<br />
This is cleaner and shorter in this case than using an If/Else.<br />
<br />
My bad, thank you again for pointing out my slip CPColin.
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I read this question with some amusement as I have a program that searches a directory looking for excel workbooks (i.e files with a .xls extension), then searches the workbook for certain worksheets, then searches the worksheets a row at a time to perform some operation on certain rows that utilizes a number of for loops each with a condition to determine if the next searched object should be skipped or not (i.e. continue). Given the example of a = 1 to 10 where a represents a row in a worksheet with the criteria I only want to work on even numbered rows (i.e. the condition to continue would be if (a % 2 = 1) continue;) &nbsp;so where a = 1 or 3 or 5 or 7 or 9, it would not perform the variable = expression statement, but increment a to 2 or 4 or 6 or 8 or 10 where it would perform the variable = expression statement. To compound matters, in certain cases, I actually need it to return not to the preceding for loop but to the one preceding that one or even to the one that precedes that one as well. Hope yours is not as complicated :-)
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jazzIIIlove,<br />
<br />
I'm not sure I deserved points for my comment; I was just agreeing with Ken Butters. Would it be okay if I opened an attention request so a moderator could reassign my points to his comment?
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<div class="content wysiwyg-content">
Hi;<br />
<br />
I have the following pseudocode:<br />

<pre><code class="code-1 nolinks" id="code-10-28333468-1"><span>for {</span>
<span>   for {</span>
<span>     for {</span>
<span>       if(condition) continue;</span>
<span>       some_variable = some_expression   </span>
</code></pre>
<br />
so if the condition is true; it will continue but continue where? next line? Also if it's false, it will continue to the next line?<br />
<br />
Regards.
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Hi;

I have the following pseudocode:
(CODE)

so if the condition is true; it will continue but continue where? next line? Also if it's false, it will continue to the next line?

Regards.

for..for.. if .. continue

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