Retrieve corresponding field in group by query

All, this should be so simple and yet I can't figure it out. I have a table containing hourly volumes for a number of days (see excerpt below).

How do I write an access query that in addition to finding the maximum "totvol" for each day also returns the hour in which TotVol occurs? So, from the table below I need to return two rows:
Day        Hour      TotVol
18-Jun-13      15      1563
19-Jun-13      5      1111

Retrieving the maximum TotVol value for each day is easy, but how do I get the associated hour?

Here are the sample data:

Day        Hour      TotVol
18-Jun-13      15      1563
18-Jun-13      16      1481
18-Jun-13      17      1231
18-Jun-13      18      990
18-Jun-13      19      941
18-Jun-13      20      750
18-Jun-13       21      629
18-Jun-13      22      483
18-Jun-13      23      275
19-Jun-13      0      201
19-Jun-13      1      148
19-Jun-13      2      161
19-Jun-13      3      234
19-Jun-13      4      542
19-Jun-13      5      1111

Microsoft OfficeMicrosoft Applications

Last Comment

mklik

8/22/2022 - Mon

Hamed Nasr

1/13/2014

Try:

Select [Day], [Hour], TotVol
From tbl
Where [TotVol] = (Select Max(TotVol) From tbl as tbl2 Where tbl.[Day]=tbl2.[Day] And tbl.[Hour]=tbl2.[Hour])

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ASKER CERTIFIED SOLUTION

Flyster

1/13/2014

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mklik

1/14/2014

ASKER

Thanks for offering your time to help me out--I tried both suggestions.

Unfortunately, hnsar's code simply replicates the original table (tblYourTable)--not sure why,

Flyster's query comes very close, but it sometimes returns two rows for the same day, with different values for TotVol and Hour. Once I joined the table and query on the day fields as well, I got the result I was looking for.

Thanks for pointing me in the right direction!

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