Xpath - search in the same node

You have to apply some logic like this,


For any Object @id,
      if Object/Fields/Field[@name='Filename'][@value='193478618937468178.000']
            then return that Object id

Checkout,
/*/Object@id/Fields/Field[@name='Filename'][@value='193478618937468178.000']

this shows syntax error:  

/*/Object@id/Fields/Field[@name='Filename'][@value='193478618937468178.000']

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//Object[Fields/Field[@name='Filename']/@value='193478618937468178.000']/@id

This gives you perfectly...

In XPATH 1.0 you can write,
//Object[Fields/Field='193478618937468178.000'[@name='Filename']]/@id
This gives you node from where you can fetch value of id.


In XPATH 2.0 you can write,
//Object[Fields/Field='193478618937468178.000'[@name='Filename']]/@id/string()

Great, Thank you very much. It works fine.

Regards Bounty

welcome

Didn't understand what's wrong with this,

In XPATH 1.0 you can write,
//Object[Fields/Field='193478618937468178.000'[@name='Filename']]/@id
This gives you node from where you can fetch value of id.

This has been tested at,
http://www.xpathtester.com/test

it is a pretty basic error actually
you are putting a predicate on a string, you need to do so on a node
the underlying data model of the xpathtester.com is wrong

you simply can't do this
/Field='193478618937468178.000'[@name='Filename']
the attribute is on the Field, so you need to do this instead
/Field[@name='Filename']='193478618937468178.000'

the closest to your solution that is valid would be something like this
//Object[Fields/Field[.='193478618937468178.000'][@name='Filename']]/@id
but I prefer mine

please don't use xpathtester if you want to be sure, it has obvious errors

For learning basic XPath1, this one is still a good reference
http://shop.oreilly.com/product/9780596002916.do

Thanks..