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Convert military time to regular in oracle

Posted on 2014-01-15
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Last Modified: 2014-01-15
select sch_date,sch_time,
       site_id,first_name,last_name
  from hbc_donor_schedule hds
 where SCH_DATE = trunc(sysdate)
   AND STATUS = 'CNFRM'
   AND PROC_CODE = 'WB'
   AND DRIVE_ID IS NULL
   and donation_type = 'AL'

This is how my data is stored in the table. I want to order by sch_time asc. How can I convert to regular time and then order by?

SCH_DATE,SCH_TIME,SITE_ID,FIRST_NAME,LAST_NAME

1/15/2014,17:00:00,LOCN100326,SANDRA,FERRIS

1/15/2014,17:40:00,LOCN200034,DEBRA,GUARASCIO

1/15/2014,12:00:00,LOCN100024,KEITH,HOELTERHOFF

1/15/2014,17:00:00,LOCN101661,DARCY,KAROUZOS
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Question by:anumoses
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slightwv (䄆 Netminder) earned 250 total points
ID: 39782572
Expected results?

Convert what you have to a date then back to a string.

Something like:
to_char(to_date(sch_time,'HH24:MI:SS'),'HH:MI:SS AM')

Order just by the date conversion:
to_date(sch_time,'HH24:MI:SS')
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LVL 76

Assisted Solution

by:slightwv (䄆 Netminder)
slightwv (䄆 Netminder) earned 250 total points
ID: 39782601
I figured maybe I had better show the date and time just in case:

to_char(to_date(SCH_DATE || SCH_TIME,'MM/DD/YYYYHH24:MI:SS'),'MM/DD/YYYY HH:MI:SS AM')

Then the order:
to_date(SCH_DATE || SCH_TIME,'MM/DD/YYYYHH24:MI:SS')
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by:anumoses
ID: 39782641
Thanks
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