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PHP get value at end of string

Posted on 2014-01-21
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Last Modified: 2014-01-22
Hi,

I'm just wondering how to get the value after the word "BUILD" in this string:

&TIMESTAMP=2014-01-21T10:23:13Z&CORRELATIONID=d2436eed33962&ACK=Success&VERSION=109&BUILD=8620107

I found this bit of code which works well for finding strings in between words here:
stackoverflow.com/questions/5696412/get-substring-between-two-strings-php

    public function getStringBetween ( $string, $start, $end ) {

        $string = " ".$string;
        $ini = strpos( $string, $start );
        if ($ini == 0) return "";
        $ini += strlen( $start );
        $len = strpos( $string, $end, $ini ) - $ini;
        return substr( $string, $ini, $len );

    }

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Handy. But I need to get the value after "BUILD".

Thank you!
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Question by:Victor Kimura
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9 Comments
 
LVL 31

Expert Comment

by:Marco Gasi
ID: 39796563
If the string has always the value you want at the end you ca do this:

$str = "&TIMESTAMP=2014-01-21T10:23:13Z&CORRELATIONID=d2436eed33962&ACK=Success&VERSION=109&BUILD=8620107";
$arr = explode("=", $str);
$wanted_value = end($arr);
//or you can use  a single line:
$wanted_value = end(explode("=", $str));

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LVL 31

Assisted Solution

by:Marco Gasi
Marco Gasi earned 167 total points
ID: 39796581
Oherwise, if BUILD can be in any place within the string you can use a simple regex:

$str = "&TIMESTAMP=2014-01-21T10:23:13Z&CORRELATIONID=d2436eed33962&ACK=Success&VERSION=109&BUILD=8620107";
$regex = "/(?<=BUILD=)\d+/";
$matches = array();
if (preg_match($regex, $str, $matches))
{
	echo "BUILD value is " . $matches[0];
}

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LVL 108

Assisted Solution

by:Ray Paseur
Ray Paseur earned 333 total points
ID: 39796757
Please see http://www.laprbass.com/RAY_temp_vkimura2007.php

I think I would not use a regular expression when PHP already has a built-in function for exactly this sort of thing.

<?php // RAY_temp_vkimura2007.php
error_reporting(E_ALL);
echo '<pre>';

// SEE http://www.experts-exchange.com/Web_Development/Web_Languages-Standards/PHP/Q_28343859.html
// REF http://www.php.net/manual/en/function.parse-str.php

// THE STRING
$str = <<<EOD
&TIMESTAMP=2014-01-21T10:23:13Z&CORRELATIONID=d2436eed33962&ACK=Success&VERSION=109&BUILD=8620107
EOD;

echo $str;
echo PHP_EOL;

parse_str($str, $out);
var_dump($out);
echo PHP_EOL;

// SHOW THE DESIRED DATA ELEMENT
echo "THE 'BUILD' IS: " . $out['BUILD'];

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0
 

Author Comment

by:Victor Kimura
ID: 39796762
@Marco,

Thanks! that's helpful! =)

I'm wondering what does the greater and equal sign in the regex mean before the BUILD and question mark?
?<=BUILD=
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Author Comment

by:Victor Kimura
ID: 39796796
@Ray,

Oh, I never knew about the parse_str(). Awesome!

What is that PHP_EOL, btw?
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Accepted Solution

by:
Ray Paseur earned 333 total points
ID: 39796852
PHP _EOL is the context-aware predefined end-of-line character.  Different OS use different line endings like \r and \n and combinations of those things.  PHP is smart enough to give us the right end-of-line for whatever we are running if we use PHP_EOL.  It makes your code more portable.  Another useful thing is DIRECTORY_SEPARATOR which gives you the correct slash for file paths.
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LVL 31

Expert Comment

by:Marco Gasi
ID: 39800028
Hi, vkimura. For some strange reason my answer about the real meaning of '?<=BUILD=' has not been posted: I'm sorry.

?<= means: look if for preceeding characters

so the piece of regex means if preceeding characters are BUILD=

Finally, that regex means: get the numbers preceeded by BUILD=

Thanks for points.
Marco
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Author Comment

by:Victor Kimura
ID: 39800372
@Marco, thank you so much for the answer! Wish I could give you more points. Next time! God bless<><
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LVL 31

Expert Comment

by:Marco Gasi
ID: 39800398
;-)
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