[Webinar] Streamline your web hosting managementRegister Today

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 180
  • Last Modified:

how do you toggle multiple images

Hi,

I have a table with some images that I would like to be able to toggle.  The trick is that when one is in the "on" state the others should be in the "off" state.

Here is the table :
<table cellspacing="7" cellpadding="0" border="0">
	<tr>
	    <td width="60" align="left">View:</td>
	    <td width="100"align="left"><a class="showAllTypes" style="cursor:pointer;"><img src="images/allTypes.png" />All Types</a></td>
	    <td width="113" align="left"><a class="showOnDemand" style="cursor:pointer;"><img src ="images/onDemand.png">On Demand</a></td>
		<td width="101" align="left"><a class="showWebinars" style="cursor:pointer;"><img src ="images/Webinars.png">Webinars</a></td>
		<td width="141" align="left"><a class="showSeminars" style="cursor:pointer;"><img src ="images/seminars.png"> Seminars</a></td>
        </tr>
        </table>

Open in new window


Just have no idea how to write the function so all the images know that when one is clicked the others will be in the off state.

Thanks,
allTypes.png
allTypesChecked.png
onDemand.png
onDemandChecked.png
seminars.png
seminarsChecked.png
webinars.png
webinarsChecked.png
0
smfmetro10
Asked:
smfmetro10
1 Solution
 
GaryCommented:
Try this

$("a").click(function(){
    $("a img").each(function(){
      $(this).attr("src",$(this).attr("src").replace("Checked.png",".png"))
    })
    $("img",this).attr("src",$("img",this).attr("src").replace(".png","Checked.png"))
})

Open in new window

0
 
smfmetro10Author Commented:
Yahoo!!!! Thanks!!
0

Featured Post

Receive 1:1 tech help

Solve your biggest tech problems alongside global tech experts with 1:1 help.

Tackle projects and never again get stuck behind a technical roadblock.
Join Now