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How To Question

Hello~

Working on a C# Visual Studios 2010 project trying to create something but having some issues. Does anyone have any suggestions on what to use when you have a list of items and you want to select one of those items, look at it, then you click on another item and look at it, without getting a ArgumentOutOfRangeException? The first item can be clicked with no error. Second item throws the error. You can click continue and it shows the item but it always throws the error. Have tried using ItemsSelectionChanged and that is what is giving the error right now. If you can just give some direction at this point on what to try that would be great.

Thanks
D
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dminx13
Asked:
dminx13
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1 Solution
 
Fernando SotoCommented:
Well without seeing the code and knowing which control/s you are using or if the second click is in a different control it is difficult to tell.

Let say you are clicking on the same control maybe a ListBox, to select multiple items you need to set SelectionMode to Multiple.

Please post more information and code and the exception message and inner exception message.
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dminx13Author Commented:
 private void InvTree_ItemSelectionChanged(object sender, ListViewItemSelectionChangedEventArgs e)
        {
            int h = e.Item.Index;
            inventory1.comboList1.ResetComboTree();
            inventory1.valueStrip1.Reset();
            var ItemData = savefile.items.items[InvTree.SelectedItems[0].Index];
            inventory1.valueStrip1.dye = Convert.ToInt32(ItemData.generator.dye_type);
            inventory1.valueStrip1.binding = Convert.ToInt32(ItemData.generator.item_binding_level);
            inventory1.valueStrip1.hireling = Convert.ToInt32(ItemData.hireling_class);
            inventory1.valueStrip1.Durability.Value = ItemData.generator.durability;
            inventory1.valueStrip1.Flags.Value = ItemData.generator.flags;
            inventory1.valueStrip1.legendary_item_level.Value = ItemData.generator.legendary_item_level;
            inventory1.valueStrip1.itemqualitylevel = ItemData.generator.item_quality_level;
            inventory1.valueStrip1.Max_Durability.Value = ItemData.generator.max_durability;
            inventory1.valueStrip1.stack_size.Value = ItemData.generator.stack_size;
            var rare_item_name = ItemData.generator.rare_item_name;
            try
            {
                inventory1.comboList1.sno_affix_string_list.Value = rare_item_name.sno_affix_string_list;
                inventory1.comboList1.item_name_is_prefix.Checked = rare_item_name.item_name_is_prefix;
                inventory1.comboList1.item_string_list_index.Value = rare_item_name.item_string_list_index;
                inventory1.comboList1.affix_string_list_index.Value = rare_item_name.affix_string_list_index;
            }
            catch { }
            this.inventory1.comboList1.SetComboTree((ComboTreeBox)this.inventory1.comboList1.ComboLayout.GetControlFromPosition(1, 0), ItemData.generator.gb_handle.gbid.ToString());
            for (int i = 0; i <= ItemData.generator.base_affixes.Count - 1; i++)
            {
                if (ItemData.generator.base_affixes.Count > 0)
                    this.inventory1.comboList1.SetComboTree((ComboTreeBox)this.inventory1.comboList1.ComboLayout.GetControlFromPosition(1, i + 1), ItemData.generator.base_affixes[i].ToString());
            }

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Fernando SotoCommented:
Please post more information and the exception message and inner exception message. Please also indicate on which line it occurs on.
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dminx13Author Commented:
Error occurs on line 6. ArgumentOutOfRangeException was unhandled. See attached screenshot.
c--Error.png
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dminx13Author Commented:
Wondering if anyone has anything more on this. I added code and error and no one has responded. I have been pulled off the project so if I don't hear anything I'll just delete this question. Thanks!
Deanna
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Fernando SotoCommented:
Run the program, when it throws the exception highlight this part of the statement on line 6,
InvTree.SelectedItems[0].Index , the right click on the highlighted part of the line and select "Add Watch". If the Watch windows was not open at the bottom of the window it will open. What is the vale in the Value column? Also what is the value in the Type column.

Also in the Exception dialog box click on the words "View Detail...", Another window will open  expand the only node, along the left side find the line with Inner Exception and post the value on that line if it has a value in it.

By the look of the exception you posted it looks as if the value might be a 'O' and not a digit.
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