Oracle SQL - Extract rightmost word in string

Posted on 2014-01-27
Medium Priority
Last Modified: 2014-01-27
Hi, I need to extract the right-most word from a field that could have multiple spaces. Example: "Administration Main Boston" = "Boston"

Question by:iamnamja
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LVL 74

Expert Comment

ID: 39812966
regexp_substr(yourstring,'[^ ]+$')

for example...

select regexp_substr('Administration Main Boston','[^ ]+$') from dual
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Assisted Solution

by:slightwv (䄆 Netminder)
slightwv (䄆 Netminder) earned 800 total points
ID: 39812967
Several ways.

Try this one:
select regexp_substr('administration main boston','[^ ]+$') from dual;
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Expert Comment

by:slightwv (䄆 Netminder)
ID: 39812976
substr/instr method:
select substr('administration main boston', instr('administration main boston',' ',-1)+1) from dual;
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Author Comment

ID: 39812985
Thank you both so much for the function.
One more question: what if I need to extract 2nd right most word? Just realized, I need to do this for some conditions. Is there a quick way to extract 2nd right most word?

"Administration Main Boston Office" = "Boston"

Thank you.
LVL 74

Accepted Solution

sdstuber earned 1200 total points
ID: 39813003
regexp_substr('Administration Main Boston Office','([^ ]+) *[^ ]+$',1,1,null,1)

or, if your version doesn't support substr back references

regexp_substr(regexp_substr('Administration Main Boston Office','[^ ]+ *[^ ]+$'),'[^ ]+')
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Expert Comment

ID: 39813010
another interesting variation for 2nd last word

reverse(regexp_substr(reverse('Administration Main Boston Office'),'[^ ]+',1,2))
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Expert Comment

ID: 39813016
you should awared a split with slightwv as well for answering the original question

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