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SUMPRODUCT Update

Hi,
Quick question, still learning how to work with sumproduct.  I have the following formula and I would like to add the criteria AS <>Yes how would I do that?

=SUMPRODUCT((MOD(ROW($AO$10:$AO$484)-ROW(AP10),2)=1)*1,$AO$10:$AO$484)
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jmac001
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jmac001
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2 Solutions
 
David L. HansenProgrammer AnalystCommented:
This should be helpful:
http://www.mrexcel.com/forum/excel-questions/460593-nesting-if-statement-sumproduct.html

Let me know if that is going to work for you or not.
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mvidasCommented:
jmac001,

Just add       $AS$10:$AS$484<>"Yes"       as an argument before the final one, like

=SUMPRODUCT((MOD(ROW($AO$10:$AO$484)-ROW(AP10),2)=1)*1,$AS$10:$AS$484<>"Yes",$AO$10:$AO$484)

Matt
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jmac001Author Commented:
Sl8zr the link was kinda of helpful but returned #value

Matt - Tried your solution and received 0 for my value? The current sum is 225 and with the updated function the new total should be 197.
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David L. HansenProgrammer AnalystCommented:
Can you post what you tried just now?
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mvidasCommented:
Is it possible to post your workbook? I'm a little puzzled by what you're trying to accomplish with your mod statement. If you're only trying to get odd numbers, try:

=SUMPRODUCT((MOD(ROW($AO$10:$AO$484),2)=1)*($AS$10:$AS$484<>"Yes")*($AO$10:$AO$484))

Matt
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barry houdiniCommented:
I think the original formula sums every other row starting with the second cell in the range

Matt's last version also does that but the reason for the  ROW(Range)-MIN(ROW(Range)) type construction is that the formula will be more robust, in that it will still return the same value, even if you insert or delete rows above the referenced range.

To retain the original robust intent but add that criteria you can use this version:

=SUMPRODUCT((MOD(ROW($AO$10:$AO$484)-ROW($AO$10),2)=1)*($AS$10:$AS$484<>"Yes"),$AO$10:$AO$484)

Note I replaced AP10 with $AO$10 as that more closely resembles the ideal setup

regards, barry
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mvidasCommented:
in that it will still return the same value, even if you insert or delete rows above the referenced range.
Nice catch. I was wondering about that
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jmac001Author Commented:
Thanks Barry and Matt, the solution worked.
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