Extract Number from AlphaNumeric string

Posted on 2014-01-29
Medium Priority
Last Modified: 2014-01-29
excel 2010 vba:

What I need:
str2  is a string variable
falpha is just my holder variable

str2 usually is  something like:   B2  C3   D34   B21   AC3    DE45    etc...

What I need:
I need a variable just to hold the Numeric part of the str2

The code below with extract the alpha part i need
If IsNumeric(Mid(str2, 2, 1)) Then
            falpha = Left(str2, 1)
              falpha = Left(str2, 2)
       End If
          str = falpha

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Question by:fordraiders
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LVL 40

Assisted Solution

als315 earned 200 total points
ID: 39818588
Dim i As Integer
Dim Str As String, c As String
Dim falpha As String, fnumeric As String
falpha = ""
fnumeric = ""
For i = 1 To Len(Str2)
    c = Mid(Str, i, 1)
    If IsNumeric(c) Then
        fnumeric = fnumeric & c
        falpha = falpha & c
    End If
Next i
Debug.Print falpha, fnumeric

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LVL 52

Accepted Solution

Rgonzo1971 earned 1600 total points
ID: 39818610

pls try

Function FindNumber(MyString As String) As Double
strFormula = "=1*MID(A1,MATCH(TRUE,ISNUMBER(1*MID(A1,ROW($1:$256),1)),0),COUNT(1*MID(A1,ROW($1:$256),1)))"
strFormula = Replace(strFormula, "A1,", Chr(34) & MyString & Chr(34) & ",")
FindNumber = Evaluate(strFormula)
End Function

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LVL 35

Assisted Solution

mvidas earned 200 total points
ID: 39818697
Simply because I couldn't pass up this question without giving a Regular Expression answer:
Function ExtractNumber(str2 As String) As String
 Dim RegEx As Object
 Set RegEx = CreateObject("vbscript.regexp")
 RegEx.Global = True
 RegEx.Pattern = "\D"
 ExtractNumber RegEx.Replace(str2, "")
End Function

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It will return whatever numbers are in the string, regardless of what is sent:
 Debug.Print ExtractNumber("B2")
 Debug.Print ExtractNumber("C3")
 Debug.Print ExtractNumber("DE45")
 Debug.Print ExtractNumber("B2  C3   D34   B21   AC3    DE45")

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Author Closing Comment

ID: 39818707

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