Oracle date question

Posted on 2014-01-31
Last Modified: 2014-02-04

   select nvl(sum(recovered_shp_liters_qty), 0)recovered_shp_qty
     from pla_quantities
    where blood_center_key = 2
      and process_date between :p_start_date and :coll_date;

I am doing a graph. For the above period I am getting the graph. Now I need to compare the graph for the data for 2012. No matter what date range they enter I have to go back to 2012.

I can hardcode p_start_date to be '01-jan-2012'
but coll_date is the one I get from the table to do year to date graph. My question is based on what the coll_date is can we get that to go back to 2012 ?
Can I use a decode or case statement to go back to 2012 of coll_date?

  and coll_date has to be
Question by:anumoses
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LVL 34

Accepted Solution

johnsone earned 250 total points
ID: 39824135
Assuming that coll_date could be any year, then this should give the same date in 2012

to_date(to_char(coll_date, 'mmddhh24miss')||'2012', 'mmddhh24missyyyy')

Author Comment

ID: 39824157
If I dont need the time stamp then will this be corect?

LVL 34

Expert Comment

ID: 39824176
Yes.  coll_date has a time portion to it (all dates do), so I was just copying what was there.  If the time portion is 00:00:00 in the original, that that will just get copied.  No harm.
LVL 32

Expert Comment

ID: 39824915
Another way -
to_date('2012','yyyy') + (coll_date - trunc(coll_date,'yy'))
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LVL 76

Expert Comment

by:slightwv (䄆 Netminder)
ID: 39825000
>>Another way -

Seems to drop a day from time to time (unless I have a typo):
select to_date('2012','yyyy') + (to_date('10/10/2013') - trunc(to_date('10/10/2013'),'yy')) from dual;
LVL 32

Expert Comment

ID: 39825047
Yeah, the problem here is that 2012 is a leap year. The difference in days of a non-leap year date and the first of that year will not produce the same day for a leap year unless the date is on or before February 28. One could create a case statement to deal with that, of course, but that might perform worse that converting to character and back to date again. :-(
LVL 34

Expert Comment

ID: 39825149
Well, if you want to get fancy, then you could do this:

add_months(coll_date, (2012 - to_number(to_char(coll_date, 'yyyy')))*12)

Still has some conversions to it though.

It would be best to stay away from using the "day" math.  Almost impossible to account for leap years, as you have seen.

Author Closing Comment

ID: 39832315

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