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Oracle date question

Posted on 2014-01-31
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Last Modified: 2014-02-04
i HAVE A QUERY

   select nvl(sum(recovered_shp_liters_qty), 0)recovered_shp_qty
     from pla_quantities
    where blood_center_key = 2
      AND RECOVERED_SHP_LITERS_QTY <> 0
      and process_date between :p_start_date and :coll_date;

I am doing a graph. For the above period I am getting the graph. Now I need to compare the graph for the data for 2012. No matter what date range they enter I have to go back to 2012.

I can hardcode p_start_date to be '01-jan-2012'
but coll_date is the one I get from the table to do year to date graph. My question is based on what the coll_date is can we get that to go back to 2012 ?
Can I use a decode or case statement to go back to 2012 of coll_date?


  and coll_date has to be
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Question by:anumoses
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johnsone earned 250 total points
ID: 39824135
Assuming that coll_date could be any year, then this should give the same date in 2012

to_date(to_char(coll_date, 'mmddhh24miss')||'2012', 'mmddhh24missyyyy')
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by:anumoses
ID: 39824157
If I dont need the time stamp then will this be corect?

TO_DATE(TO_CHAR(COLL_DATE, 'MMDD')||'2012', 'MMDDYYYY')
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by:johnsone
ID: 39824176
Yes.  coll_date has a time portion to it (all dates do), so I was just copying what was there.  If the time portion is 00:00:00 in the original, that that will just get copied.  No harm.
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Expert Comment

by:awking00
ID: 39824915
Another way -
to_date('2012','yyyy') + (coll_date - trunc(coll_date,'yy'))
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Expert Comment

by:slightwv (䄆 Netminder)
ID: 39825000
>>Another way -

Seems to drop a day from time to time (unless I have a typo):
select to_date('2012','yyyy') + (to_date('10/10/2013') - trunc(to_date('10/10/2013'),'yy')) from dual;
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by:awking00
ID: 39825047
Yeah, the problem here is that 2012 is a leap year. The difference in days of a non-leap year date and the first of that year will not produce the same day for a leap year unless the date is on or before February 28. One could create a case statement to deal with that, of course, but that might perform worse that converting to character and back to date again. :-(
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Expert Comment

by:johnsone
ID: 39825149
Well, if you want to get fancy, then you could do this:

add_months(coll_date, (2012 - to_number(to_char(coll_date, 'yyyy')))*12)

Still has some conversions to it though.

It would be best to stay away from using the "day" math.  Almost impossible to account for leap years, as you have seen.
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Author Closing Comment

by:anumoses
ID: 39832315
thanks
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