<div>
You may try to use an IF function like:<br />
<br />
=IF(J13=0,0,J12/J13)<br />
<br />
Sincerely,<br />
<br />
Ed
</div>


You may try to use an IF function like:

=IF(J13=0,0,J12/J13)

Sincerely,

Ed

<div>
Hello,<br />
<br />
test the values of the cells first, especially the J13 cell. Also, you don't need to wrap a division into a Sum() function.<br />
<br />
=if(J13&gt;0,J12/J13,&quot;&quot;)<br />
<br />
This formula will only undertake the division if the value in cell J13 is greater than Zero. If it is not greater than zero, it will just return an empty text value.<br />
<br />
cheers, teylyn
</div>


Hello,

test the values of the cells first, especially the J13 cell. Also, you don't need to wrap a division into a Sum() function.

=if(J13>0,J12/J13,"")

This formula will only undertake the division if the value in cell J13 is greater than Zero. If it is not greater than zero, it will just return an empty text value.

cheers, teylyn

<div>
use your formula with IFERROR like this:<br />
<b>=IFERROR(SUM(J12/J13);&quot;&quot;)</b><br />
<br />
see in my sample<br />
<a href="https://filedb.experts-exchange.com/incoming/2014/02_w06/832386/sample.xlsx" target="_blank" class="file-inline" title="sample (9 KB)"><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 512 512"><path d="M67.508 468.467c-58.005-58.013-58.016-151.92 0-209.943l225.011-225.04c44.643-44.645 117.279-44.645 161.92 0 44.743 44.749 44.753 117.186 0 161.944l-189.465 189.49c-31.41 31.413-82.518 31.412-113.926.001-31.479-31.482-31.49-82.453 0-113.944L311.51 110.491c4.687-4.687 12.286-4.687 16.972 0l16.967 16.971c4.685 4.686 4.685 12.283 0 16.969L184.983 304.917c-12.724 12.724-12.73 33.328 0 46.058 12.696 12.697 33.356 12.699 46.054-.001l189.465-189.489c25.987-25.989 25.994-68.06.001-94.056-25.931-25.934-68.119-25.932-94.049 0l-225.01 225.039c-39.249 39.252-39.258 102.795-.001 142.057 39.285 39.29 102.885 39.287 142.162-.028A739446.174 739446.174 0 0 1 439.497 238.49c4.686-4.687 12.282-4.684 16.969.004l16.967 16.971c4.685 4.686 4.689 12.279.004 16.965a755654.128 755654.128 0 0 0-195.881 195.996c-58.034 58.092-152.004 58.093-210.048.041z"/></svg>sample.xlsx</a>
</div>


use your formula with IFERROR like this:
=IFERROR(SUM(J12/J13);"")

see in my sample
sample.xlsx [https://filedb.experts-exchange.com/incoming/2014/02_w06/832386/sample.xlsx]

sample.xlsx

<div>
<div class="content wysiwyg-content">
When I put in a formula with a division I get #DIV/0! anytime there is a zero or null value, how can this me returned as just blank?<br />
<br />
Sample<br />
<br />
=SUM(J12/J13)
</div>
</div>


When I put in a formula with a division I get #DIV/0! anytime there is a zero or null value, how can this me returned as just blank?

Sample

=SUM(J12/J13)

Getting rid of the dreaded #DIV/0!

Microsoft Excel topics include formulas, formatting, VBA macros and user-defined functions, and everything else related to the spreadsheet user interface, including error messages.