Find middle row in table

you need to use a ROW_NUMBER() function here, compared with the COUNT(*) result (or the max of the row numbering ...

;with data as ( select t.*, row_number() over (order by foo) rn from yourtable )
select * 
from data
where rn = ( select ( max(x.rn) / 2 ) + 1 from data x) 

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now, what if the count(*) returns 2 (an even number...), what row to return? row 1 or row 2 ?

depending on what you want, you will use floor() or ceiling():

;with data as ( select t.*, row_number() over (order by foo) rn from yourtable )
select * 
from data
where rn = ( select floor( max(x.rn) / 2 ) + 1 from data x) 

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hope this helps

Thanks for that. I've changed the field and table names to suit my requirement but t.* is not being recognised as valid code. It may just be me being slow (it has been a long day!).

assuming your table has a serial key (IDENTITY) column like I have in this case that can be done simply like:

select * from Clients with (nolock)
where Clientid = (select count(Clientid)/2 from clients with (nolock));