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Spring : Unable to read from a properties file

Posted on 2014-02-04
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Last Modified: 2014-02-11
I have a bean defined

	<bean id="placeholderConfigurer"
		class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
		<property name="locations">
			<list>
				<value>classpath:project.properties</value>
			</list>
		</property>
		<property name="ignoreUnresolvablePlaceholders" value="true"/>
	</bean>


    <bean id="processor" class="com.util.Processor">    	 
    	<property name="system" value="${system}"/>
    </bean>

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In project.properties i have
system = TECH-UK

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My Processor

public class Processor implements BeanDefinitionRegistryPostProcessor
{
private String system;

	public void setSystem(String system) {
		this.system = system;
	}


	public String getSystem() {
		return system;
	}

@Override
    public void postProcessBeanDefinitionRegistry(BeanDefinitionRegistry registry) throws BeansException {

  //create beans
}

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When i put a break point on this line >>this.system = system;
I expect to see value of system as TECH-UK but i see ${system}

I think the problem is with implementing BeanDefinitionRegistryPostProcessor
When i comment out the  'implements BeanDefinitionRegistryPostProcessor' i see the value TECH-UK

Any idea how i can fix this.

Thanks
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Comment
Question by:royjayd
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7 Comments
 
LVL 36

Expert Comment

by:mccarl
ID: 39834185
I think the problem is with implementing BeanDefinitionRegistryPostProcessor
Spot on! The reason why it doesn't replace the ${system} with its value is because PropertyPlaceholderConfigurer is implemented as a BeanFactoryPostProcessor too. And when Spring is initializing an ApplicationContext it instantiates ALL BeanFactoryPostProcessors before any of them get invoked. So by the time that the PropertyPlaceholderConfigurer gets a chance to replace the ${system} with TECH-UK, your Processor has already been instantiated and the setSystem() method has already been called with ${system} as the argument.

More correctly, since you implement BeanDefinitionRegistryPostProcessor, these actually get instantiated and invoked before even regular BeanFactoryPostProcessors so there is definitely no chance to get the placeholder resolved.

Unfortunately, there is no way around this, basically BeanFactoryPostProcessors (and the sub-interface BeanDefinitionRegistryPostProcessor) don't mix well with PropertyPlaceholderConfigurer. You would need to do something quite different to what you have above, such as... inject the location of the .properties file directly into your Processor and have it load it into a Properties object and then resolve the value of the "system" property, etc.
0
 

Author Comment

by:royjayd
ID: 39834399
>>You would need to do something quite different to what you have above, such as.. inject the location of the .properties file directly into your processor and have it load into a Properties object...

Lets say I create a Properties object which contains the entires present in my properties file,
how do I set it to BeanDefinitionRegistryPostProcessor ?

Can you please provide some sample code or link if available..

Thanks for the prompt response.
0
 
LVL 36

Accepted Solution

by:
mccarl earned 500 total points
ID: 39834443
I was thinking more like this...
public class Processor implements BeanDefinitionRegistryPostProcessor
{
	private String system;

	public void setPropertiesLocation(Resource location) {
		Properties props = new Properties();
		props.load(location.getInputStream());
		this.system = props.getProperty("system");
	}

@Override
    public void postProcessBeanDefinitionRegistry(BeanDefinitionRegistry registry) throws BeansException {

  //create beans
}

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And then your spring config just looks like this...
    <bean id="processor" class="com.util.Processor">    	 
    	<property name="propertiesLocation" value="classpath:project.properties"/>
    </bean>

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Author Comment

by:royjayd
ID: 39848882
Thanks..
Any help with my next question will be greatly appreciated.
http://www.experts-exchange.com/Programming/Languages/Java/Q_28361464.html
0
 
LVL 36

Expert Comment

by:mccarl
ID: 39849064
No worries, glad to help! :)
0
 
LVL 36

Expert Comment

by:mccarl
ID: 39849070
Any help with my next question will be greatly appreciated.
Sorry, I have 0 experience with Drools! Hope someone else can help you.
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Author Comment

by:royjayd
ID: 39849916
No worries :)
Thx.
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