Query 2 quarter data

Hello,
I'm working with data that includes 6 months of results (counting the current month).  Using DateAdd I've been able to get the data to go back to the first of the month so it captures the entire data regardless of the current date.  Hopefully that makes sense.  So for example as of today it's pulling in 9/1/2013 - today.  So now I need to capture (from this data) 2 quarters, the current quarter and the previous quarter.  My logic is I want it to include the full three months of the previous quarter (so it would ignore the September data because I don't have the full quarter represented) and the current quarter no matter how much of it I have.  It's a running data sort of thing.  Can this be done?  I've tried to DateAdd using "q" but it's not liking my logic.  Any assistance would be great.  Hopefully you can understand what I'm after.  

Thanks in advance!

Sarah
LVL 1
SarahDaisy8Asked:
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als315Connect With a Mentor Commented:
Sorry, Sarah, my solution was wrong - it will not work for every 3-rd month. We can correct it:
(DateDiff("m",[Dt],Date())-3-Choose(Month(Date()) Mod 3+1,3,1,2))<0

You can use function and it is right way if you don't want to use web database. You can trust Gustav's solution. He is the best in date functions.

I can explain my idea:
1. Calculate month's number in current quarter:
Month(Date()) Mod 3
remainder after number is divided by 3
result will be 1 for January, April, 2 for February, May, but 0 for March and June
But we need values 1, 2, 3, so we can use Choose function for correct values: 1, 2, 3
Index in this function should start from 1, so we should add 1 to Mod's result:
Choose(Month(Date()) Mod 3+1,3,1,2)
You like to have all previous quarter, so you should add 3:
Now we can go back with DateDiff and get result
It can also be done with function:
Function check_date(Dt As Date) As Boolean
Dim M As Integer, N As Integer
M = Month(Date) Mod 3
check_date = False
Select Case M
    Case 0
        N = 6
    Case 1
        N = 4
    Case 2
        N = 5
End Select
If DateDiff("m", Dt, Date) - N < 0 Then check_date = True
End Function

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Database2-1.accdb
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als315Commented:
You can use this equation ([Dt] is your date field):
DateDiff("m",[Dt],Date())-Month(Date()) Mod 3-3
if result is < 0, date is in expected range
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John_VidmarConnect With a Mentor Commented:
The following determines which quarter contains todays date, and then goes back 2 quarters:
select	DateAdd(quarter,-2,	case	when Month(current_timestamp) IN (1,2,3) then '01/01/'
					when Month(current_timestamp) IN (4,5,6) then '04/01/'
					when Month(current_timestamp) IN (7,8,9) then '07/01/'
					else '10/01/'
				end + cast(Year(current_timestamp) as varchar))

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Gustav BrockCIOCommented:
You can use the generic functions below to create a filter:

Where [YourDateField] Between DatePreviousQuarterFirst() And DateThisQuarterLast()

However, as you have no data later than the current date, you can use:

Where [YourDateField] Between DatePreviousQuarterFirst() And Date()

Public Function DatePreviousQuarterFirst( _
  Optional ByVal datDateThisQuarter As Date) As Date
  
  Const cintQuarterMonthCount   As Integer = 3
  
  Dim intThisMonth              As Integer
  
  If datDateThisQuarter = 0 Then
    datDateThisQuarter = Date
  End If
  intThisMonth = (DatePart("q", datDateThisQuarter) - 1) * cintQuarterMonthCount

  DatePreviousQuarterFirst = DateAdd("q", -1, DateSerial(Year(datDateThisQuarter), intThisMonth + 1, 1))

End Function


Public Function DateThisQuarterLast( _
  Optional ByVal datDateThisQuarter As Date) As Date
  
  Const cintQuarterMonthCount   As Integer = 3
  
  Dim intThisMonth              As Integer
  
  If datDateThisQuarter = 0 Then
    datDateThisQuarter = Date
  End If
  intThisMonth = DatePart("q", datDateThisQuarter) * cintQuarterMonthCount
  
  DateThisQuarterLast = DateSerial(Year(datDateThisQuarter), intThisMonth + 1, 0)

End Function

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/gustav
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SarahDaisy8Author Commented:
These are all great solutions, thank you!  Ace, with yours I was able to use it (not quite understanding what it was doing, but it works) but I put <4 instead and got exactly what I needed.  However, I'm not sure that will be sufficient for when my data moves into the start of October.  What do you think?  Thanks!
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als315Commented:
I can't agree with -4. You can test it. Look at sample
Database2.accdb
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SarahDaisy8Author Commented:
Thanks Als315. I'll test it when I get home but I trust you heh. So is there no way of getting around using a function?  Though I suppose it's just called in the query, right?  Thanks again.

Sarah
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SarahDaisy8Author Commented:
Thank you so much for these solutions! I'm so sorry for the delay in reply.  Ace, I'm able to use your solution.  Thank you so much for your time!

-Sarah
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