asked on

calculate Median sql 2012

I need to calculate the Median of quotes based on BusinessUnit, and can't figure out why the following code are not working:

;with QuoteCount as
(
SELECT
BusinessUnit,
FullName,
CAST(DATEDIFF(dd, 0, CreatedOn) AS datetime) as CreatedOn,
Count( QuoteId) as Quotes
FROM
      quote
WHERE
       BusinessUnit IN (@BusinessUnit)
      AND (CAST(DATEDIFF(dd, 0, CreatedOn) AS datetime) BETWEEN @StartDate AND @EndDate)
GROUP BY
      BusinessUnit,
      FullName,
      CAST(DATEDIFF(dd, 0, CreatedOn) AS datetime)
)

,Median_all as
(
SELECT DISTINCT BusinessUnit, Quotes,
PERCENTILE_CONT(0.5)
WITHIN GROUP (ORDER BY Quotes)
OVER (PARTITION BY BusinessUnit) AS MedianContAll
FROM QuoteCount
WHERE @BusinessUnit= null
ORDER BY BusinessUnit DESC
)

,Median as
(
SELECT DISTINCT BusinessUnit, Quotes,
PERCENTILE_CONT(0.5)
WITHIN GROUP (ORDER BY Quotes)
OVER (PARTITION BY BusinessUnit) AS MedianCont
FROM QuoteCount
WHERE BusinessUnit in (@BusinessUnit)
ORDER BY BusinessUnit DESC
)
select
qc.BusinessUnit,
qc.fullname,
qc.CreatedOn,
sum(qc.Quotes) as Quotes,
max(m.MedianCont) as MedianCont,
max(ma.MedianContAll ) as MedianContAll
from
      Median_all ma
     inner join Median m on m.BusinessUnit=ma.BusinessUnit
      inner join QuoteCount qc on ma.BusinessUnit=qc.BusinessUnit
group by
qc.BusinessUnit,
qc.fullname,
qc.CreatedOn
order by
qc.BusinessUnit,
qc.fullname,
qc.CreatedOn

Thank you in advance.

ASKER CERTIFIED SOLUTION

Kevin Cross

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sharon2011

ASKER

Kevin Cross,

Sorry for the delayed response. I removed the @BusinessUnit = Null. Instead Union all the query with all BusinessUnit. Then use the following code:

, ALLBUROWNum as
(
select grp, cnt, ROW_NUMBER() over (order by cnt) as n
from AllBUWeightCount

)

,findALLBUMedian as
(
select ceiling(max(n)/2.0) as n
from ALLBUROWNum
union all
select ceiling(max(n)/2.0)+1 as n
from ALLBUROWNum
having max(n) % 2 = 0
)

, AllBUMedian as
(
SELECT C.grp, AVG(1. * c.cnt) AS AllBUMedian
FROM ALLBUROWNum AS C
INNER JOIN findALLBUMedian AS f
on C.n = f.n
GROUP BY C.grp
)

Thank you so much for your immediate assistance.