Solved

thread synchronization

Posted on 2014-02-07
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Last Modified: 2014-03-14
Hi,

I am working on below example

http://www.avajava.com/tutorials/lessons/how-do-i-use-a-synchronized-block-in-a-static-method.html


I have not understood what author is trying to demonstrate as below

It's possible to synchronize a static method. When this occurs, a lock is obtained for the class itself. This is demonstrated by the static hello() method in the SyncExample class below. When we create a synchronized block in a static method, we need to synchronize on an object, so what object should we synchronize on? We can synchronize on the Class object that represents the class that is being synchronized. This is demonstrated in the static goodbye() method of SyncExample. We synchronize on SyncExample.class.


I got below output which is not clear to me
hello
goodbye

please advise
Any links resources ideas highly appreciated. Thanks in advance
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Question by:gudii9
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6 Comments
 
LVL 35

Expert Comment

by:mccarl
ID: 39843986
Yeah, that example is not that good because you would get the same output even if you remove the synchronize modifer/block.

The main point that it is trying to convey is that the two methods have the same functionality. Putting the synchronized keyword in the method declaration (like in hello() method) is essentially the same as using the synchronized block (like in goodbye() method) with this class as the argument, ie. SyncExample.class
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LVL 7

Author Comment

by:gudii9
ID: 39850790
you would get the same output even if you remove the synchronize modifer/block.



you mean below synchronized block inside goodbye() method right?
public static void goodbye() {
            synchronized (SyncExample.class) {
                  System.out.println("goodbye");
            }
When you say removing  synchronize modifer/block means as below right comment those two lines?


public class SyncExample {

	public static void main(String[] args) {
		hello();
		goodbye();
	}

	public static synchronized void hello() {
		System.out.println("hello");
	}

	public static void goodbye() {
		//synchronized (SyncExample.class) {
			System.out.println("goodbye");
	//	}
	}

}

Open in new window

Can you please point me to better practical example on this concept to understand clearly.

Please advise
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LVL 7

Author Comment

by:gudii9
ID: 39870576
Please advise
0
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LVL 35

Accepted Solution

by:
mccarl earned 500 total points
ID: 39872245
Yes, I meant the synchronized block inside the goodbye method, and yes you can do it the way you did. I also meant that you can take the synchronized keyword out of the definition for the hello method (line 8).

The point of my comment though was more around the fact that that program all runs within the one thread, there is no multithreading and so the synchronized make no difference.

As for an example that does make proper use of it, it is a bit hard for me to do one or find one right at the moment. I'll try and get back to you soon with one.
0
 
LVL 7

Author Comment

by:gudii9
ID: 39880860
I'll try and get back to you soon with one.

Sure.
0
 
LVL 7

Author Comment

by:gudii9
ID: 39880871
using the synchronized block (like in goodbye() method) with this class as the argument, ie. SyncExample.class

Can there be synchronized blocks without any argument(like class name)?
Is that is possible?
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