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Escape single quotes

Posted on 2014-02-08
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Last Modified: 2014-02-16
I have a shell script (below) that scans through directories and reads in files with a .arf extension (sample below), and then adds the contents of the file to a main SQL file to insert into a database.  This works perfectly, except I now need to escape any single quotes found.

Shell Script:
#!/bin/sh

echo `date`
find . -name "*.arf" | while read f; do
  newpath="$(basename $(dirname "$f"))"
#/$(basename $f)"
  cat "$f" | gawk -F'[:"]' -v p="$newpath" '{ 
      nlist=nlist "`, `" $1;
      vlist=vlist ", '\''" $3 "'\''";
  }
  END { 
    printf "insert into `database`.`archives` (`NEWPATH%s`) values ('\''%s'\''%s);\n", nlist, p, vlist;
  }' >> myinsertfile.sql
#| tee -a myinsertfile.sql
  cnt=$((cnt+1))
  [ $(($cnt%100)) -eq 0 ] && echo "File #$cnt: $f"
done

echo "Total Files: $cnt"

echo `date`

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Sample problem .arf file:
FILEID: "TIF521496"
PATH: "/optical/incoming/TIF521496"
TYPE: "TIF"
SECLEV: "10"
STATID: ""
USRID: "admin"
REQDATE: "12/31/2012"
REQTIME: "08:28:17"
GENDATE: "01/02/2013"
GENTIME: "08:28:17"
PROGID: ""
GROUPID: "Drive up rec's"
DESC: "December"

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Question by:bdhtechnology
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2 Comments
 
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Accepted Solution

by:
woolmilkporc earned 500 total points
ID: 39844105
Escape the single quote with a backslash? Try this:
cat "$f" | gawk -F'[:"]' -v p="$newpath" '{ 
      nlist=nlist "`, `" $1;
      gsub("'\''","'\\\\\''",$3);
      vlist=vlist ", '\''" $3 "'\''";
  }
  END { 
    printf "insert into `database`.`archives` (`NEWPATH%s`) values ('\''%s'\''%s);\n", nlist, p, vlist;
  }' >> myinsertfile.sql

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Note line 3!
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Author Comment

by:bdhtechnology
ID: 39863036
Perfect, that is exactly what I needed!
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