• Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 229
  • Last Modified:

Return only employees with contracts with two or more departments

I have three tables; employees (e), departments (d) and contracts (c)
Each employee can have one or more contracts with one or more departments

Example:
Karen: 2 contracts, both with dep A
John: 1 contract with dep A, 2 contracts with dep B
Lisa: 2 contracts with dep C, 2 contracts with dep D
Peter: 1 contract with dep A      
            

SELECT e.empID, e.name, e.uid, d.depID, d.depname, d.locaton from
employees e
LEFT JOIN contracts c ON c.empID=e.empID
LEFT JOIN departments d ON d.depID=c.depID

Open in new window

- returns all employees with all departments they have a contract with

But: I want only those who has contracts with two or more departments.
In the example above: John and Lisa. Karen and Peter has contracts with only one dep.

I guess it would be something like:
SELECT e.empID, e.name, e.uid, d.depID, d.depname, d.locaton, COUNT(DISTINCT something) from
employees e
LEFT JOIN contracts c ON c.empID=e.empID
LEFT JOIN departments d ON d.depID=c.depID
GROUP BY  something
HAVING the group by > 1

Open in new window

- without returning Karen, since she has contract with only one dep, and Peter who has only one contract with one dep
0
fmsol
Asked:
fmsol
  • 2
2 Solutions
 
Surendra NathTechnology LeadCommented:
You can do that by the below query, but you can get only the employee name and employee ID.

SELECT e.empID, e.name, e.uid
employees e
JOIN contracts c ON c.empID=e.empID
JOIN departments d ON d.depID=c.depID
GROUP BY  e.empID, e.name , e.uid
HAVING COUNT(1) > 1

Open in new window

0
 
Surendra NathTechnology LeadCommented:
If you want all the details including the contract details then you can use the below query and if you are using SQL Server 2005 or above version.

;WITH C AS
(
SELECT e.empID, e.name, e.uid, d.depID, d.depname, d.locaton
,row_number() OVER(partition by e.empID, e.name, e.uid order by e.empID, e.name, e.uid) RN
from employees e
JOIN contracts c ON c.empID=e.empID
JOIN departments d ON d.depID=c.depID
)
SELECT * FROM C c0 WHERE EXISTS ( SELECT 1 FROM C c1 and c0.empid = c1.empid and c0.uid = c1.uid WHERE RN >= 2)
                                  

Open in new window

0
 
awking00Commented:
Can you describe the contracts and department tables?  I assume there would be attributes in the contracts table, such as contractid that could be used to get the counts, and attributes in either or both of the two tables, such as contractwithdepartment in the contracts table or contractsresponsiblefor in the departments table, that can tie them together. Perhaps some sample data for all three tables and the expected output would help.
0
 
Scott PletcherSenior DBACommented:
SELECT e.empID, e.name, e.uid, d.depID, d.depname, d.locaton
FROM (
    SELECT e.empID
    FROM employees e
    INNER JOIN contracts c ON c.empID=e.empID
    GROUP BY e.empID
    HAVING COUNT(DISTINCT c.depID) > 1
) AS e_multi_dept
INNER JOIN employees e ON e.empID=e_multi_dept.empID
LEFT JOIN contracts c ON c.empID=e.empID
LEFT JOIN departments d ON d.depID=c.depID
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

Join & Write a Comment

Featured Post

Cloud Class® Course: Microsoft Office 2010

This course will introduce you to the interfaces and features of Microsoft Office 2010 Word, Excel, PowerPoint, Outlook, and Access. You will learn about the features that are shared between all products in the Office suite, as well as the new features that are product specific.

  • 2
Tackle projects and never again get stuck behind a technical roadblock.
Join Now