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VB Command to move cursor to first empty row of table

Posted on 2014-02-13
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Last Modified: 2014-02-13
I am recording an Excel macro and need it to select the first empty field at the bottom of a particular column.  The number of rows in the column will vary every time I run the macro.  

I've figured out a way to have the macro move to the last row of data of the column with this command:

Selection.End(xlDown).Select

If column F has 8 rows of data, the above lands me on F8.  But I then need to move the cursor down one more row to F9.  When I use the macro recorder, Excel records a literal address of F9 like this:

Range("F9").Select

But the next time I run it column F might have 10 rows of data.  What command do I use to move down one?
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Question by:witzph1
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LVL 22

Expert Comment

by:Flyster
ID: 39856603
Try something like this:

I= Selection.End(xlDown).Select
Range("F"& I+1).Range

Flyster
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LVL 33

Accepted Solution

by:
Norie earned 500 total points
ID: 39856669
Try this.
Range("F" & Rows.Count).End(xlUp).Offset(1).Select

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Author Closing Comment

by:witzph1
ID: 39857112
This gives does exactly what I need and does it in the most elegant fashion. Thank you!
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LVL 22

Expert Comment

by:Flyster
ID: 39857941
I agree. Nice code imnorie!
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