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Query to fetch rows with matching values for just few columns column as a single row

Posted on 2014-02-14
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Last Modified: 2014-02-25
Hello,
I have a table with rows having same id and code value, but different Effective date.
Id         Code          EffectiveDate     cost
1          basic          01-jan-2010        5.00
1          basic          06-feb-2011        5.00
1          exclusive    09-aug-2012        15.00

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My query needs to return only 2 rows, one for 1 basic, and another for 1 exclusive.
Result should be like:
Id            Code                 cost
1              Basic                5.00
1              Exclusive          15.00

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DISTINCT would not work as the Effective date is different between the two records with Id=1 and Code = 'Basic'.

Thanks!
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Question by:sath350163
3 Comments
 
LVL 69

Assisted Solution

by:ScottPletcher
ScottPletcher earned 250 total points
ID: 39860782
I assume you want the latest date??  You don't indicate anything about which row should be selected and why ... and they both have the same price?!

SELECT
    id, code, cost
FROM (
    SELECT id, code, cost,
        ROW_NUMBER() OVER(PARTITION BY id ORDER BY EffectiveDate DESC) AS row_num
    FROM tablename
) AS derived
WHERE
    row_num = 1
0
 
LVL 69

Expert Comment

by:Éric Moreau
ID: 39861308
select distinct id, code, cost
from YourTable
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LVL 142

Accepted Solution

by:
Guy Hengel [angelIII / a3] earned 250 total points
ID: 39861780
both code above would work, but I will just post my article for you to understand the issue and find sql code solutions like above:
http://www.experts-exchange.com/Database/Miscellaneous/A_3203-DISTINCT-vs-GROUP-BY-and-why-does-it-not-work-for-my-query.html
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