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Oracle - Max effective dates and Max invalid date

Posted on 2014-02-15
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Last Modified: 2014-02-15
Hi

I've got this Query where i would like to get the result of the RD.EFFECTIVE_DATE and the Max RP.DATE_INVALID.

even if i put Max in front of TO_CHAR (RD.EFFECTIVE_DATE, 'yyyymmdd') AS EFFECTIVE_DATE,, it just don't work.

How can i do that?

Thanks for your help.


SELECT   'H',
         'M',
         R.ID,
         TO_CHAR (RD.EFFECTIVE_DATE, 'yyyymmdd') AS EFFECTIVE_DATE,
         TO_CHAR (RP.DATE_INVALID, 'yyyymmdd') AS INVALID_DATE,
         R.BREAK_TYPE,
         RATE_UNIT,
         CURRENCY_CODE,
         R.RATE_MEASURE,
         INCREMENTAL_FLAG,
         REF_NAME,
         'D',
         'M',
         RD.RADIAL_RATE_ID,
         TO_CHAR (RD.EFFECTIVE_DATE, 'yyyymmdd') AS EFFECTIVE_RATE,
         RD.MAX_BREAK,
         RD.UNIT_RATE,
         RD.CONSTANT_CHARGE,
         RD.MIN_CHARGE,
         RD.MAX_CHARGE
  FROM   RADIAL_RATE R, RADIAL_RATE_DETAIL RD, RADIAL_RATE_PERIOD RP
 WHERE   R.ID = RD.RADIAL_RATE_ID AND RD.RADIAL_RATE_ID = RP.RADIAL_RATE_ID AND R.ID = RP.RADIAL_RATE_ID
 ORDER BY R.ID;

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Question by:Wilder1626
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6 Comments
 
LVL 73

Expert Comment

by:sdstuber
Comment Utility
you mean something like this?


SELECT   'H',
         'M',
         R.ID,
         TO_CHAR (RD.EFFECTIVE_DATE, 'yyyymmdd') AS EFFECTIVE_DATE,
         TO_CHAR (RP.DATE_INVALID, 'yyyymmdd') AS INVALID_DATE,
         R.BREAK_TYPE,
         RATE_UNIT,
         CURRENCY_CODE,
         R.RATE_MEASURE,
         INCREMENTAL_FLAG,
         REF_NAME,
         'D',
         'M',
         RD.RADIAL_RATE_ID,
         TO_CHAR (RD.EFFECTIVE_DATE, 'yyyymmdd') AS EFFECTIVE_RATE,
         RD.MAX_BREAK,
         RD.UNIT_RATE,
         RD.CONSTANT_CHARGE,
         RD.MIN_CHARGE,
         RD.MAX_CHARGE,
         max(RD.EFFECTIVE_DATE) over() max_effective,
        max(RP.DATE_INVALID) over() max_invalid
  FROM   RADIAL_RATE R, RADIAL_RATE_DETAIL RD, RADIAL_RATE_PERIOD RP
 WHERE   R.ID = RD.RADIAL_RATE_ID AND RD.RADIAL_RATE_ID = RP.RADIAL_RATE_ID AND R.ID = RP.RADIAL_RATE_ID
 ORDER BY R.ID;



if not,  please post sample data and expected output
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LVL 11

Author Comment

by:Wilder1626
Comment Utility
Hi sdstuber

I still see weird results.

With the query you provided me, i still have the same result from my previous one.

Please look at the attachment.

You will see 2 sheets.

Query sheet is the result of the above SQL and in Result needed, what i'm expecting to receive.

You will also see the e tables:
RADIAL_RATE
RADIAL_RATE_DETAIL
RADIAL_RATE_PERIOD

Let me know if something can be done.

Thanks  for your help.
extract.xls
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LVL 73

Expert Comment

by:sdstuber
Comment Utility
the sample and expected looked like they had output from my incorrect query

going back to your original query though it looks like you're just trying to get one row for which ever one has the max of those 2 columns

so, just order by those descending and take whatever comes out on top


SELECT *
  FROM (SELECT 'H',
               'M',
               r.id,
               TO_CHAR(rd.effective_date, 'yyyymmdd') AS effective_date,
               TO_CHAR(rp.date_invalid, 'yyyymmdd') AS invalid_date,
               r.break_type,
               rate_unit,
               currency_code,
               r.rate_measure,
               incremental_flag,
               ref_name,
               'D',
               'M',
               rd.radial_rate_id,
               TO_CHAR(rd.effective_date, 'yyyymmdd') AS effective_rate,
               rd.max_break,
               rd.unit_rate,
               rd.constant_charge,
               rd.min_charge,
               rd.max_charge
          FROM radial_rate r, radial_rate_detail rd, radial_rate_period rp
         WHERE r.id = rd.radial_rate_id
           AND rd.radial_rate_id = rp.radial_rate_id
           AND r.id = rp.radial_rate_id
        ORDER BY rd.effective_date DESC, rp.date_invalid DESC)
 WHERE ROWNUM = 1
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LVL 11

Author Comment

by:Wilder1626
Comment Utility
I think it would work if i only have one ID.

Ex: 4TRACKS_PH37'.

But if i have 100 different IDs with multiple dates just like 4TRACKS_PH37'. I would get all most up to date for each IDs.

I'm just trying it and i only get 1 record (1 ID) when i should get about 145 different ones.
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Accepted Solution

by:
sdstuber earned 500 total points
Comment Utility
In that case you use row_number analytic, partitioning by your id

Same idea, but each id gets it's own counter


SELECT *
  FROM (SELECT 'H',
               'M',
               r.id,
               TO_CHAR(rd.effective_date, 'yyyymmdd') AS effective_date,
               TO_CHAR(rp.date_invalid, 'yyyymmdd') AS invalid_date,
               r.break_type,
               rate_unit,
               currency_code,
               r.rate_measure,
               incremental_flag,
               ref_name,
               'D',
               'M',
               rd.radial_rate_id,
               TO_CHAR(rd.effective_date, 'yyyymmdd') AS effective_rate,
               rd.max_break,
               rd.unit_rate,
               rd.constant_charge,
               rd.min_charge,
               rd.max_charge,
               ROW_NUMBER()
                   OVER(PARTITION BY r.id ORDER BY rd.effective_date DESC, rp.date_invalid DESC)
                   rn
          FROM radial_rate r, radial_rate_detail rd, radial_rate_period rp
         WHERE r.id = rd.radial_rate_id
           AND rd.radial_rate_id = rp.radial_rate_id
           AND r.id = rp.radial_rate_id)
 WHERE rn = 1
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Author Closing Comment

by:Wilder1626
Comment Utility
Thanks for your help.

just went over all records and i have a perfect match.

Thanks again
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