Link to home
Start Free TrialLog in
Avatar of Wilder1626
Wilder1626Flag for Canada

asked on

Oracle - Max effective dates and Max invalid date

Hi

I've got this Query where i would like to get the result of the RD.EFFECTIVE_DATE and the Max RP.DATE_INVALID.

even if i put Max in front of TO_CHAR (RD.EFFECTIVE_DATE, 'yyyymmdd') AS EFFECTIVE_DATE,, it just don't work.

How can i do that?

Thanks for your help.


SELECT   'H',
         'M',
         R.ID,
         TO_CHAR (RD.EFFECTIVE_DATE, 'yyyymmdd') AS EFFECTIVE_DATE,
         TO_CHAR (RP.DATE_INVALID, 'yyyymmdd') AS INVALID_DATE,
         R.BREAK_TYPE,
         RATE_UNIT,
         CURRENCY_CODE,
         R.RATE_MEASURE,
         INCREMENTAL_FLAG,
         REF_NAME,
         'D',
         'M',
         RD.RADIAL_RATE_ID,
         TO_CHAR (RD.EFFECTIVE_DATE, 'yyyymmdd') AS EFFECTIVE_RATE,
         RD.MAX_BREAK,
         RD.UNIT_RATE,
         RD.CONSTANT_CHARGE,
         RD.MIN_CHARGE,
         RD.MAX_CHARGE
  FROM   RADIAL_RATE R, RADIAL_RATE_DETAIL RD, RADIAL_RATE_PERIOD RP
 WHERE   R.ID = RD.RADIAL_RATE_ID AND RD.RADIAL_RATE_ID = RP.RADIAL_RATE_ID AND R.ID = RP.RADIAL_RATE_ID
 ORDER BY R.ID;

Open in new window

Avatar of Sean Stuber
Sean Stuber

you mean something like this?


SELECT   'H',
         'M',
         R.ID,
         TO_CHAR (RD.EFFECTIVE_DATE, 'yyyymmdd') AS EFFECTIVE_DATE,
         TO_CHAR (RP.DATE_INVALID, 'yyyymmdd') AS INVALID_DATE,
         R.BREAK_TYPE,
         RATE_UNIT,
         CURRENCY_CODE,
         R.RATE_MEASURE,
         INCREMENTAL_FLAG,
         REF_NAME,
         'D',
         'M',
         RD.RADIAL_RATE_ID,
         TO_CHAR (RD.EFFECTIVE_DATE, 'yyyymmdd') AS EFFECTIVE_RATE,
         RD.MAX_BREAK,
         RD.UNIT_RATE,
         RD.CONSTANT_CHARGE,
         RD.MIN_CHARGE,
         RD.MAX_CHARGE,
         max(RD.EFFECTIVE_DATE) over() max_effective,
        max(RP.DATE_INVALID) over() max_invalid
  FROM   RADIAL_RATE R, RADIAL_RATE_DETAIL RD, RADIAL_RATE_PERIOD RP
 WHERE   R.ID = RD.RADIAL_RATE_ID AND RD.RADIAL_RATE_ID = RP.RADIAL_RATE_ID AND R.ID = RP.RADIAL_RATE_ID
 ORDER BY R.ID;



if not,  please post sample data and expected output
Avatar of Wilder1626

ASKER

Hi sdstuber

I still see weird results.

With the query you provided me, i still have the same result from my previous one.

Please look at the attachment.

You will see 2 sheets.

Query sheet is the result of the above SQL and in Result needed, what i'm expecting to receive.

You will also see the e tables:
RADIAL_RATE
RADIAL_RATE_DETAIL
RADIAL_RATE_PERIOD

Let me know if something can be done.

Thanks  for your help.
extract.xls
the sample and expected looked like they had output from my incorrect query

going back to your original query though it looks like you're just trying to get one row for which ever one has the max of those 2 columns

so, just order by those descending and take whatever comes out on top


SELECT *
  FROM (SELECT 'H',
               'M',
               r.id,
               TO_CHAR(rd.effective_date, 'yyyymmdd') AS effective_date,
               TO_CHAR(rp.date_invalid, 'yyyymmdd') AS invalid_date,
               r.break_type,
               rate_unit,
               currency_code,
               r.rate_measure,
               incremental_flag,
               ref_name,
               'D',
               'M',
               rd.radial_rate_id,
               TO_CHAR(rd.effective_date, 'yyyymmdd') AS effective_rate,
               rd.max_break,
               rd.unit_rate,
               rd.constant_charge,
               rd.min_charge,
               rd.max_charge
          FROM radial_rate r, radial_rate_detail rd, radial_rate_period rp
         WHERE r.id = rd.radial_rate_id
           AND rd.radial_rate_id = rp.radial_rate_id
           AND r.id = rp.radial_rate_id
        ORDER BY rd.effective_date DESC, rp.date_invalid DESC)
 WHERE ROWNUM = 1
I think it would work if i only have one ID.

Ex: 4TRACKS_PH37'.

But if i have 100 different IDs with multiple dates just like 4TRACKS_PH37'. I would get all most up to date for each IDs.

I'm just trying it and i only get 1 record (1 ID) when i should get about 145 different ones.
ASKER CERTIFIED SOLUTION
Avatar of Sean Stuber
Sean Stuber

Link to home
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
Start Free Trial
Thanks for your help.

just went over all records and i have a perfect match.

Thanks again