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MVC 5 VB.Net Application Trouble

Posted on 2014-02-18
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Last Modified: 2014-04-13
Hi,

I'm editing the vbhtml file to loop through records to match in a small demo app I'm making,

Here's how it seems to work in C#:
 @foreach (var item in Model.Enrollments)
    {
        <tr>
            <td>
                @Html.DisplayFor(modelItem => item.Course.Title)
            </td>
            <td>
                @Html.DisplayFor(modelItem => item.Grade)
            </td>
            <td>
                @Html.DisplayFor(modelItem => item.Course.Credits)
            </td>
        </tr>
    }

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I attempted to convert it to vb, but I'm getting errors... I'm sure it's simple but I'm completely new to mvc...

        @For Each item In Model.Times
             
        <tr>
            <th>
                @item.Activity.ToString 
            </th>

            <th>
                @item.StartTime.ToString  
            </th>

            <th>
                @item.EndTime.ToString 
            </th>
        </tr>
        
        Next
                
    </table>

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It gives errors on the HTML tags "<th>" and "<th/>" :

"Attribute specifier is not a complete statement.  Use a line continuation to apply the attribute to the following statement."

Any help greatly appreciated.

Thanks
~j
0
Comment
Question by:prosit
  • 2
3 Comments
 
LVL 7

Expert Comment

by:Kishan Zunjare
ID: 39869482
Your possible solution can be;

@For Each item In Model.Times             
     <tr>
	@<td>@item.Activity.ToString</td>
 	@<td>@item.StartTime.ToString</td>
	@<td>@item.EndTime.ToString </td>
     </tr>        
Next

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0
 
LVL 2

Accepted Solution

by:
prosit earned 0 total points
ID: 39876880
Yeah that didn't work either, basically I had to encapsulate the TR in a text tag:

@For Each item In Model.Times            
  @<text>
     <tr>
      @<td>@item.Activity.ToString</td>
       @<td>@item.StartTime.ToString</td>
      @<td>@item.EndTime.ToString </td>
     </tr>  
  @</text>    
Next
0
 
LVL 2

Author Closing Comment

by:prosit
ID: 39997100
Found my own solution!
0

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