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Oracle - Query issue

Hi

I have this below query that pulls data from 1 single table:

SELECT   LOAD_ID, STOP_NUM, LOCATION_ID, MILES, MILES_INDICATOR    
    FROM   LOAD_STOP
   WHERE   OPEN_TIME  > TO_DATE (TO_CHAR (SYSDATE, 'YYYYMMDD'), 'YYYYMMDD') - 7
ORDER BY   LOAD_ID, STOP_NUM;

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What i'm trying to do is to find every MILES_INDICATOR that equals '4' and then, it will take the LOCATION_ID of the same row as the FROM value, then take the LOCATION_ID of the following row as the TO value.

The data must be sorted as : ORDER BY LOAD_ID, STOP_NUM.

How can i do that?

In the attachment, you will see 2 sheets:

1- Table extract = an example of the data in the table: LOAD_STOP
2- Final result = what i would like to see as the final result from the query

Thanks again for your help.
Table-result.xls

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Surrano

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Wilder1626

ASKER

This is perfect

Thanks for your help

johnsone

Well, I guess I was a little late.

This should do it without having to join the table to itself. Should perform much better and should handle cases where there are gaps in the STOP_NUM field.

SELECT * 
FROM   (SELECT load_id, 
               stop_num, 
               location_id            "FROM", 
               miles, 
               miles_indicator, 
               Lead(location_id) 
                 over ( 
                   PARTITION BY load_id 
                   ORDER BY stop_num) "TO" 
        FROM   load_stop 
        WHERE  open_time > Trunc(SYSDATE) - 7) 
WHERE  miles_indicator = 4 
ORDER  BY load_id, 
          stop_num;

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There is no OPEN_TIME field in the sample data that you supplied, so I assume it is in that table. Also, removed the unnecessary conversions on SYSDATE.

There are also syntax errors in the accepted answer. The ORDER BY has ambiguous column names. They need to be prefixed with the correct table alias.

Wilder1626

ASKER

Hi johnsone

Thanks for still giving me some more ideas. I will test this and come back to you.