Access query syntax - division by zero in aggregate function

Dear experts -
hopefully an easy one.
I am calculate an average using the formula below - which works well, however i want to avoid division by zero, which is giving me a #Num! error for certain results.

Any suggestions?
Thanks!

TR_Reg: Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,[e].[billrate],0))/Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,1,0))

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terpsichoreAsked:
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Rgonzo1971Connect With a Mentor Commented:
Hi,

Maybe

TR_Reg: Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,[e].[billrate],0))/IIF(Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,1,0))=0,null,Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,1,0)))

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Regards
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Gustav BrockCIOCommented:
This is one method, to first check if the sum is zero:

TR_Reg:
IIf(Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,1,0))=0, 0,
Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,[e].[billrate],0))/Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,1,0)))

/gustav
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terpsichoreAuthor Commented:
This worked - thank you.
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