• Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 938
  • Last Modified:

Access query syntax - division by zero in aggregate function

Dear experts -
hopefully an easy one.
I am calculate an average using the formula below - which works well, however i want to avoid division by zero, which is giving me a #Num! error for certain results.

Any suggestions?
Thanks!

TR_Reg: Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,[e].[billrate],0))/Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,1,0))

Open in new window

0
terpsichore
Asked:
terpsichore
1 Solution
 
Rgonzo1971Commented:
Hi,

Maybe

TR_Reg: Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,[e].[billrate],0))/IIF(Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,1,0))=0,null,Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,1,0)))

Open in new window

Regards
0
 
Gustav BrockCIOCommented:
This is one method, to first check if the sum is zero:

TR_Reg:
IIf(Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,1,0))=0, 0,
Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,[e].[billrate],0))/Sum(IIf([e].[billunit]=1 And [e].[volumeunit]=1 And [accounts].[regulatory]=True And [e].[action_ID]=38,1,0)))

/gustav
0
 
terpsichoreAuthor Commented:
This worked - thank you.
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

Join & Write a Comment

Featured Post

What Kind of Coding Program is Right for You?

There are many ways to learn to code these days. From coding bootcamps like Flatiron School to online courses to totally free beginner resources. The best way to learn to code depends on many factors, but the most important one is you. See what course is best for you.

Tackle projects and never again get stuck behind a technical roadblock.
Join Now