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SELECT Records based on octal or decimal value at the end of a string

Posted on 2014-02-25
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Last Modified: 2014-02-25
I need to select records from a table if they have a certain decimal value at the end of the string.  After an import we get many records that contain decimal value 13 as the final character.  I determined that based on doing a dump in PL/SQL.

select '('||website||')', dump(website)
from business
----------

I get the following:
(sunshinecavaliers.com ), Typ=1 Len=22:115,117,110,115,104,105,110,101,99,97,118,97,108,105,101,114,115,46,99,111,109,13

Now, that I know my problem records contain a decimal value of '13' I want to search my entire DB to find all records that contain the '13' at the end of the website field.
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Question by:bretthonn13
7 Comments
 
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Expert Comment

by:YZlat
ID: 39886475
SELECT * FORM TAble1 WHERE Field1 LIKE '%13'
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Accepted Solution

by:
sdstuber earned 2000 total points
ID: 39886490
decimal character 13 is a carriage return rather than searching on the dump output
just search for that character



select '('||website||')', dump(website)
from business
where website like '%' || chr(13)


note, looking for trailing characters is not normally going to be something you can use an index, so this query might take a while if you have many rows
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Expert Comment

by:awking00
ID: 39886532
select * from business
where instr(website,chr(13)) = length(website);
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Expert Comment

by:sdstuber
ID: 39886539
>>>  instr(website,chr(13)) = length(website);

same idea as LIKE '%' ||13 but more expensive to execute
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Expert Comment

by:awking00
ID: 39886564
I agree and wouldn't have even posted my suggestion except I wrote it much earlier but never submitted it after I received a phone call and never even saw the other responses. I was going to withdraw it, but apparently cannot after a new comment has been submitted. You're just too fast, Sean :-)
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Author Comment

by:bretthonn13
ID: 39886798
decimal character 13 is a carriage return rather than searching on the dump output
just search for that character



select '('||website||')', dump(website)
from business
where website like '%' || chr(13)


It works great.  Unfortunately I have far more records with problems than I thought.  I should be able to update those records and simply remove the chr(13) though right?
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LVL 74

Expert Comment

by:sdstuber
ID: 39886869
doing the update is easy, but only you can decide if it's ok to do so or not.

update business
set website = rtrim(website,chr(13))
where website like '%' || chr(13)
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