how to open a FileDialog in microsoft access 2013 on a specific location

hi

i use this code on a form to open a file dialog
Function selectFile()
Dim fd As FileDialog, fileName As String
Set fd = Application.FileDialog(msoFileDialogFilePicker)
'disable multiselect for one file selection
fd.AllowMultiSelect = False
 
If fd.Show = True Then
    fileName = fd.SelectedItems(1)
End If
 
'clear file dialog
Set fd = Nothing
 
'Return File name and path
selectFile = fileName
 
End Function

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how can i set that the dialog box will show a specific location for example it's will show files on the  location "c:\example\"
bill201Asked:
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N-WConnect With a Mentor Commented:
On line 6 of your code, add:
fd.InitialFileName = "c:\example"

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zorvek (Kevin Jones)ConsultantCommented:
To open a file open dialog in a specific directory, change the default directory before showing the dialog. In this example I'm setting the default directory to the desktop:

   ChDir CreateObject("Wscript.Shell").SpecialFolders("Desktop")

Kevin
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bill201Author Commented:
in what line should i put this line of code?
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zorvek (Kevin Jones)Connect With a Mentor ConsultantCommented:
Before the line that shows the dialog.

Before this line would work:

ChDir CreateObject("Wscript.Shell").SpecialFolders("Desktop")
Set fd = Application.FileDialog(msoFileDialogFilePicker)

Kevin
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Rey Obrero (Capricorn1)Connect With a Mentor Commented:
Function selectFile()
Dim fd As FileDialog, fileName As String
Set fd = Application.FileDialog(msoFileDialogFilePicker)
'disable multiselect for one file selection

'ADD this line

fd.initialfilename =  "c:\example\"


fd.AllowMultiSelect = False
 
If fd.Show = True Then
    fileName = fd.SelectedItems(1)
End If
 
'clear file dialog
Set fd = Nothing
 
'Return File name and path
selectFile = fileName
 
End Function
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bill201Author Commented:
thanks a lot for every one
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