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how to open a FileDialog in microsoft access 2013 on a specific location

Posted on 2014-02-25
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Last Modified: 2014-02-25
hi

i use this code on a form to open a file dialog
Function selectFile()
Dim fd As FileDialog, fileName As String
Set fd = Application.FileDialog(msoFileDialogFilePicker)
'disable multiselect for one file selection
fd.AllowMultiSelect = False
 
If fd.Show = True Then
    fileName = fd.SelectedItems(1)
End If
 
'clear file dialog
Set fd = Nothing
 
'Return File name and path
selectFile = fileName
 
End Function

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how can i set that the dialog box will show a specific location for example it's will show files on the  location "c:\example\"
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Question by:bill201
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6 Comments
 
LVL 81

Expert Comment

by:zorvek (Kevin Jones)
ID: 39887648
To open a file open dialog in a specific directory, change the default directory before showing the dialog. In this example I'm setting the default directory to the desktop:

   ChDir CreateObject("Wscript.Shell").SpecialFolders("Desktop")

Kevin
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Author Comment

by:bill201
ID: 39887657
in what line should i put this line of code?
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LVL 8

Accepted Solution

by:
N-W earned 668 total points
ID: 39887658
On line 6 of your code, add:
fd.InitialFileName = "c:\example"

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LVL 81

Assisted Solution

by:zorvek (Kevin Jones)
zorvek (Kevin Jones) earned 668 total points
ID: 39887660
Before the line that shows the dialog.

Before this line would work:

ChDir CreateObject("Wscript.Shell").SpecialFolders("Desktop")
Set fd = Application.FileDialog(msoFileDialogFilePicker)

Kevin
0
 
LVL 120

Assisted Solution

by:Rey Obrero (Capricorn1)
Rey Obrero (Capricorn1) earned 664 total points
ID: 39887662
Function selectFile()
Dim fd As FileDialog, fileName As String
Set fd = Application.FileDialog(msoFileDialogFilePicker)
'disable multiselect for one file selection

'ADD this line

fd.initialfilename =  "c:\example\"


fd.AllowMultiSelect = False
 
If fd.Show = True Then
    fileName = fd.SelectedItems(1)
End If
 
'clear file dialog
Set fd = Nothing
 
'Return File name and path
selectFile = fileName
 
End Function
0
 

Author Comment

by:bill201
ID: 39887663
thanks a lot for every one
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