Using DCOUNT in Continuous SubForm (or similar)

Hi,

I have a continuous subform that has a text field in it.  This text field is set to ;
=DCount("[CustomerNumber]", "tblOrders", "[CustomerNumber] = 888")


The DCOUNT bit works fine!

However,  for example, if there are 4 records shown in the continuous form then ALL of them have there text field updated.

I (obviously) ONLY want ONE record of the sub form updated.  I.e. the record that I have just amended.

Perhaps, you have seen this issue before?
Patrick O'DeaAsked:
Who is Participating?
 
Dale FyeCommented:
Working from iPad, so cannot open your file.

Does the resulting recordset (the one shown in your continuous form) need to be updateable?

If not you could create a subquery:

SELECT [Registration], COUNT([City]) as CitiesSeenIn
FROM (SELECT DISTINCT [Registration], [City] FROM tblCarsSpotted) as DistinctSpotings

And then join this to your Cars table on the Registration field.
0
 
PatHartmanCommented:
Access maintains only a single set of form properties.  That is why in a continuous or datasheet view, all instances of an unbound control show the same value.

We need to know more about what you are trying to count to advise further.  It is possible to use DCount() in a query although I don't recommend it.  If you use it in the query, you will be able to bind the control to a column from the query and so each row can show a different value.
0
 
Patrick O'DeaAuthor Commented:
Thanks for the help so far.

I attach a simple example.

1. There are 4 cities in tblCity.

2. I am monitoring cars (!) in the city.  I am writing the registration plate of each car seen in the city.  These registration numbers are help in tblCarsSpotted.

3. You will note that car reg L999 J120 has been seen in more than one city!

4. I want to see in the yellow box the NUMBER of cities that each car has been seen.

5. For example, the number 3 should appear in the yellow box for every occurrence of registration L999 J120.


How do I achieve item number 5?
CarsTemp.accdb
0
 
Patrick O'DeaAuthor Commented:
Thanks folks.
I have decided not to use this function after all.
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.