SQL Pivot - All Dates

I currently have SQL that creates a pivot based on PERIOD, but excludes dates (INS_DATE) where no data exists.  How can I get it to show all dates whether data exists or not?

WITH BASEQUERY AS(
SELECT INS_DATE, CONVERT(VARCHAR(5),INSERT_PERIOD,108) as PERIOD, BOOKINGS
FROM SUMMARY
WHERE CATEGORY IN('WEB')
)
SELECT * FROM BASEQUERY
pivot (SUM(BOOKINGS) for PERIOD in (
[00:00],[00:30],[01:00],[01:30],[02:00],[02:30],
[03:00],[03:30],[04:00],[04:30],[05:00],[05:30],
[06:00],[06:30],[07:00],[07:30],[08:00],[08:30],
[09:00],[09:30],[10:00],[10:30],[11:00],[11:30],
[12:00],[12:30],[13:00],[13:30],[14:00],[14:30],
[15:00],[15:30],[16:00],[16:30],[17:00],[17:30],
[18:00],[18:30],[19:00],[19:30],[20:00],[20:30],
[21:00],[21:30],[22:00],[22:30],[23:00],[23:30])) AS SUMBOOKINGSPERPERIOD
ORDER BY 1 ASC

Open in new window

Cody VanceSr. Analyst - ERPAsked:
Who is Participating?
 
PortletPaulConnect With a Mentor freelancerCommented:
here is an article discussing creation of a date table
http://www.experts-exchange.com/Database/MS-SQL-Server/A_12267-Date-Fun-Part-One-Build-your-own-SQL-calendar-table-to-perform-complex-date-expressions.html

& here is sample code using a recursive CTE
-- establish a date range
DECLARE @fromdate datetime
      , @todate datetime
SELECT
        @fromdate = '20130901' 
      , @todate   = '20131001'

;WITH
        DateCTE (theDate)
        AS (
                SELECT
                        @fromdate AS theDate
                UNION ALL
                        SELECT
                                DATEADD(DAY, 1, theDate)
                        FROM DateCTE
                        WHERE theDate < dateadd(day,-1,@todate)
                )
SELECT
        *
FROM DateCTE
left join SUMMARY on DateCTE.theDate = SUMMARY.INS_DATE
...

Open in new window

0
 
YZlatCommented:
Can you post a sample of original data?
0
 
Cody VanceSr. Analyst - ERPAuthor Commented:
I cannot unfortunately..
0
Cloud Class® Course: SQL Server Core 2016

This course will introduce you to SQL Server Core 2016, as well as teach you about SSMS, data tools, installation, server configuration, using Management Studio, and writing and executing queries.

 
YZlatCommented:
which data is missing BOOKINGS or INSERT_PERIOD?
0
 
YZlatCommented:
What you can do is replace the null values with a string:

WITH BASEQUERY AS(
SELECT INS_DATE, CONVERT(VARCHAR(5),INSERT_PERIOD,108) as PERIOD, ISNULL(BOOKINGS, 'NULL') as BOOKINGS
FROM SUMMARY
WHERE CATEGORY IN('WEB')
)
SELECT * FROM BASEQUERY
pivot (SUM(BOOKINGS) for PERIOD in (
[00:00],[00:30],[01:00],[01:30],[02:00],[02:30],
[03:00],[03:30],[04:00],[04:30],[05:00],[05:30],
[06:00],[06:30],[07:00],[07:30],[08:00],[08:30],
[09:00],[09:30],[10:00],[10:30],[11:00],[11:30],
[12:00],[12:30],[13:00],[13:30],[14:00],[14:30],
[15:00],[15:30],[16:00],[16:30],[17:00],[17:30],
[18:00],[18:30],[19:00],[19:30],[20:00],[20:30],
[21:00],[21:30],[22:00],[22:30],[23:00],[23:30])) AS SUMBOOKINGSPERPERIOD
ORDER BY 1 ASC

Open in new window

0
 
Cody VanceSr. Analyst - ERPAuthor Commented:
Here is an example, as you can see it starts at 2/12/13 since there is no data for 1/1/13-2/11/13.  I need it to show these dates, even if it shows NULL all the way across.

Data
0
 
PortletPaulfreelancerCommented:
With respect to the dates that are not present is the results:

You need a table of dates first, then left join your data to that.

This table of dates could be a permanent feature or something temporary (e.g. a recursive CTE)

----
posting data: >>"I cannot unfortunately.."

but you could post "sample data" (or "representative data") that is stripped of anything private.
0
 
YZlatCommented:
Did you try my solution?
0
 
PortletPaulfreelancerCommented:
YZlat, the question as I understand it is about missing rows.

>>"How can I get it to show all dates whether data exists or not?"
0
 
Cody VanceSr. Analyst - ERPAuthor Commented:
This worked perfectly, thank you!!!!
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.