Get value from a programatically created textbox

Hello,

I am creating a textbox and attaching it to a table using this code...

            if (controlType == "textbox")
            {
                HtmlTableRow row = new HtmlTableRow();
                HtmlTableCell cell1 = new HtmlTableCell();
                HtmlTableCell cell2 = new HtmlTableCell();

                System.Web.UI.WebControls.Label label = new System.Web.UI.WebControls.Label();
                System.Web.UI.WebControls.TextBox textbox = new System.Web.UI.WebControls.TextBox();
                label.ID = "Label" + rowCount.ToString();
                label.Text = r["ControlText"].ToString();
                textbox.ID = r["ControlName"].ToString();

                cell1.Width = "200px";
                cell1.Controls.Add(label);
                cell2.Controls.Add(textbox);
                row.Cells.Add(cell1);
                row.Cells.Add(cell2);

                tableControls.Rows.Add(row);
            }

Open in new window


I am trying to get the value of the textbox using this code, but the TextBox I create always has a null value.

TextBox t = this.FindControl(controlName) as TextBox;

Open in new window


Any ideas?
LVL 1
tatton777Asked:
Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

x
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

Pratima PharandeCommented:
I tried this and working fine for me
check and let us know if any issue

 protected void Page_Load(object sender, EventArgs e)
    {
        HtmlTableRow row = new HtmlTableRow();
        HtmlTableCell cell1 = new HtmlTableCell();
        HtmlTableCell cell2 = new HtmlTableCell();

        System.Web.UI.WebControls.Label label = new System.Web.UI.WebControls.Label();
        System.Web.UI.WebControls.TextBox textbox = new System.Web.UI.WebControls.TextBox();
        label.ID = "Label1";
        label.Text = "Label1";
        textbox.ID = "Text1";

        cell1.Width = "200px";
        cell1.Controls.Add(label);
        cell2.Controls.Add(textbox);
        row.Cells.Add(cell1);
        row.Cells.Add(cell2);
        tableControls.Rows.Add(row);
     

    }
    protected void Button1_Click(object sender, EventArgs e)
    {
        TextBox t = this.FindControl("Text1") as TextBox; 

        Response.Write(t.Text);
    }

Open in new window

0
tatton777Author Commented:
I am not having luck.

The control is embedded in a RadAjaxPanel (like an updatepanel).

I tried using the RadAjaxPanel.FindControl but that didn't work either. Any more ideas?
0
Daniel Van Der WerkenIndependent ConsultantCommented:
I've had problems in the past with controls located on Ajax update panels.

http://msdn.microsoft.com/en-us/library/bb386454.aspx

What I've found is that a control that is in an update panel won't register properly with a control that isn't. So, they either need to be in the same update panel or they need ot be both in separate update panels with UpdateMode-"Conditional" in the ASPX page for the UpdatePanel and do a .Update() in the code-behind.

Either that, or use JQuery if possible. That get the value regardless.
0
Amazon Web Services

Are you thinking about creating an Amazon Web Services account for your business? Not sure where to start? In this course you’ll get an overview of the history of AWS and take a tour of their user interface.

tatton777Author Commented:
Hello,

I removed the updatepanel and the controls still aren't found.

The controls are added programatically in the page_load. I'm reading that since they are loaded in the page_load event that they may have to be recreated. Is that true?
0
tatton777Author Commented:
I ended up getting help elsewhere. You have to load the table with the controls on EVERY POSTBACK once the set of controls is instantiated. You can do this on the Page_Load or the Page_Init, it doesn't matter.

    //==================================================
    // Page_Load()
    //==================================================
    protected void Page_Load(object sender, EventArgs e)
    {
        if(!Page.IsPostBack)
        {

        }
        if(sv.FillPdfPageFormControls != null)
            LoadTableWithPdfControls(sv.FillPdfPageFormControls);
    }

    //==================================================
    // LoadTableWithPdfControls()
    //==================================================
    protected void LoadTableWithPdfControls(DataTable formContols)
    {
        int rowCount = 1;

        foreach (DataRow r in formContols.Rows)
        {
            string controlType = r["ControlType"].ToString().ToLower().Trim();

            if (controlType == "spacer")
            {
                TableRow row = new TableRow();
                TableCell cell = new TableCell();
                cell.ColumnSpan = 2;
                cell.Text = " ";
                row.Cells.Add(cell);                
                
                TableControls.Rows.Add(row);
                TableControls.Rows.Add(row);
            }

            if (controlType == "label")
            {
                TableRow row = new TableRow();
                TableCell cell = new TableCell();

                System.Web.UI.WebControls.Label label = new System.Web.UI.WebControls.Label();
                label.Text = r["ControlText"].ToString();
                label.ID = r["ControlName"].ToString();
                cell.ColumnSpan = 2;
                cell.Controls.Add(label);
                row.Cells.Add(cell);
                TableControls.Rows.Add(row);
            }

            if (controlType == "textbox")
            {
                TableRow row = new TableRow();
                TableCell cell1 = new TableCell();
                TableCell cell2 = new TableCell();

                System.Web.UI.WebControls.Label label = new System.Web.UI.WebControls.Label();
                System.Web.UI.WebControls.TextBox textbox = new System.Web.UI.WebControls.TextBox();
                label.ID = "Label" + rowCount.ToString();
                label.Text = r["ControlText"].ToString();

                //TextBox wk = (TextBox)this.TableControls.FindControl(r["controlName"].ToString());

                textbox.ID = r["ControlName"].ToString();

                cell1.Width = 200;
                cell1.Controls.Add(label);
                cell2.Controls.Add(textbox);
                row.Cells.Add(cell1);
                row.Cells.Add(cell2);

                TableControls.Rows.Add(row);
            }

            if (controlType == "checkbox")
            {
                TableRow row = new TableRow();
                TableCell cell1 = new TableCell();
                TableCell cell2 = new TableCell();

                System.Web.UI.WebControls.CheckBox checkbox = new System.Web.UI.WebControls.CheckBox();

                checkbox.Text = r["ControlText"].ToString();
                checkbox.ID = r["ControlName"].ToString();

                cell2.Controls.Add(checkbox);
                row.Cells.Add(cell1);
                row.Cells.Add(cell2);
                TableControls.Rows.Add(row);
            }
            rowCount += 1;
        }
    }

Open in new window

0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
tatton777Author Commented:
Because I solved my own problem. Why else would I be choosing myself as the provider of the solution? I hired two programmers to help me with this. One failed utterly, the other helped me get this solved. I decided that I would share the fix with the experts-exchange community.

Take care.
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
C#

From novice to tech pro — start learning today.