jquery ajax .done to selector

Why does returnedval += "hello" + data not end up in the input box?
options.cmd does end up in the input box.
I thought by naming a variable returnedval and appending to it in the .done section that I would get the ajax data value.




function runPlugIn(el)
{
      $(el).closest('div').find('input[type=text]').runner({'cmd':'HREmpmstr'})
      
}


(function ( $ ) {
      
      
    $.fn.runner = function( options ) {
      var returnedval = options.cmd
 
      $.ajax({data:{'cmd':options.cmd},url: 'PLUGINW/runners/runner.asp'}).done(function(data) {returnedval += "hello" + data});
      
      
      return $(this).each(function(){$(this).val(returnedval)})
       

    };
 
}( jQuery ));
KeithMcElroyAsked:
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KeithMcElroyAuthor Commented:
adding async: false makes it work, however, is that a good practice?
0
GaryCommented:
async:false is bad, as you won't be able do anything else on the page til the script finishes

.done has nothing to do with waiting for the ajax call to be returned.

	  $.ajax({data:{'cmd':options.cmd},context:this,url: 'PLUGINW/runners/runner.asp',
		success:function(data) {
			returnedval += "hello" + data
			return returnedval
		}
	  });

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