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Determine max number of characters in any cell in a column in excel, using VBA

Posted on 2014-03-01
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Last Modified: 2014-03-06
Using VBA, I need to determine the maximum number of characters in a column of anywhere from 20,000 to 200,000 records, using VBA.

I found a reference that indicates I can do this with an Array function in a cell by doing something like:  =MAX(Len(A1:A20000))) and then hitting Ctrl-Shift-Enter  which wraps the function in { }, but I need to do this in code, and need to do it for multiple columns, so it would be great if the solution involved a column# rather than an alpha representation of the column.
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Question by:Dale Fye (Access MVP)
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12 Comments
 
LVL 43

Expert Comment

by:Saqib Husain, Syed
ID: 39897180
Try this

col = 3
rw = 2000
Range("A1").FormulaArray = "=max(len(r1c" & col & ":R" & rw & "C" & col & "))"
0
 
LVL 47

Author Comment

by:Dale Fye (Access MVP)
ID: 39897192
Any way to do that without pushing the value to a cell first, just going straight to a variable:

intMaxColLen = ????
0
 
LVL 45

Expert Comment

by:aikimark
ID: 39897969
@ssaqibh

Unfortunately, you can't use worksheetfunctions, since the Len() function is not a worksheet function.

You can create a user defined function for this.
Option Explicit

Public Function MaxLen(parmRange As Range) As Long
    Dim strItem As String
    Dim lngMaxLen As Long
    Dim lngLen As Long
    Dim rngCell As Range
    lngMaxLen = Len(parmRange.Cells(1, 1).Value)
    For Each rngCell In parmRange
        lngLen = Len(rngCell.Value)
        If lngMaxLen < lngLen Then
            lngMaxLen = lngLen
        Next
    Next
    MaxLen = lngMaxLen
End Function

Open in new window

You can get even more performance if you copy the range into a variant array and iterate the array.  This is the inverse of the technique I showed in my Fast Data Push to Excel article.
http://www.experts-exchange.com/A_2253.html
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LVL 81

Expert Comment

by:byundt
ID: 39898077
LEN is a perfectly valid worksheet function, so saqibh's approach will definitely work.

Rather than troll through an entire column of cells, it is more efficient to restrict it to the used range. I modified aikimark's function to do just that, adding in his suggestion of copying the range into a variant.
Public Function MaxLen(parmRange As Range) As Long
    Dim lngLen As Long
    Dim v As Variant, vData As Variant
    vData = Intersect(parmRange.Worksheet.UsedRange, parmRange).Value
    For Each v In vData
        If Len(v) > lngLen Then lngLen = Len(v)
    Next
    MaxLen = lngLen
End Function

Open in new window

0
 
LVL 43

Expert Comment

by:Saqib Husain, Syed
ID: 39898181
Not very elegant but to avoid the loop I would have tried something like

col = 3
rw = 20000
tmp = Cells(1, col + 1).FormulaR1C1
Cells(1, col + 1).FormulaArray = "=max(len(r1c" & col & ":R" & rw & "C" & col & "))"
intMaxColLen = Cells(1, col + 1).Value
Cells(1, col + 1).FormulaR1C1 = tmp
0
 
LVL 45

Expert Comment

by:aikimark
ID: 39898671
when I wrote that you can't use worksheet functions, I meant that in the context of a VBA routine.  There is certainly a Len() function that can be used in a formula.
0
 
LVL 85

Accepted Solution

by:
Rory Archibald earned 500 total points
ID: 39899891
You could use Evaluate:

Sub GetLength(lColumn As Long)
   MsgBox Evaluate("MAX(LEN(" & Application.ConvertFormula("R1C" & lColumn & ":R20000C" & lColumn, xlR1C1, xlA1) & "))")
End Sub

Open in new window


Of course, you could pass the row number as well rather than using a fixed number, or pass a range using Cells if you only have a column Number.
0
 
LVL 81

Expert Comment

by:byundt
ID: 39900662
Rory,
I get a type mismatch with your code in Excel 2013 whenever there are more than 255 cells being tested. Your sub works when there are 255 or fewer cells being tested.

Brad
0
 
LVL 85

Expert Comment

by:Rory Archibald
ID: 39900705
Brad,

I can't reproduce that. Just ran a quick test with 800 odd cells populated in a column with no problems. Can you provide a workbook?

Rory
0
 
LVL 81

Expert Comment

by:byundt
ID: 39900807
Rory,
The type mismatch occurred in Excel 2013 when I ran your macro from the Immediate pane command line. But when I ran it from a command button on the worksheet in response to your Comment requesting a workbook, your code worked. Hmm...

So I rebooted my computer (both Mac and Parallels), and now your code works both on the Immediate pane command line and when called from a worksheet command button. It also works when I turn your one-liner into a UDF called from a worksheet formula.

My computer must have had some corruption that was cured by rebooting.

I apologize for the false accusation.

Brad
0
 
LVL 85

Expert Comment

by:Rory Archibald
ID: 39900821
No worries. :)
0
 
LVL 47

Author Closing Comment

by:Dale Fye (Access MVP)
ID: 39910319
This worked well, since I already had the workbook open and knew how many rows to include in the string.

Thanks, Rory.
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