Solved

php mysql to write a pro gram to make invoice

Posted on 2014-03-01
2
1,050 Views
Last Modified: 2014-04-25
I try to write a program for head of invoice and detail of each invoice

what wrong with the last line of the code please suggest

creditebalance.name = $nameofbill



<?php
header ('Content-type: text/html; charset=utf-8');

?>
<?php require_once('../Connections/connect.php'); ?>
<?php
if (!function_exists("GetSQLValueString")) {
function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") 
{
  if (PHP_VERSION < 6) {
    $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue;
  }

  $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue);

  switch ($theType) {
    case "text":
      $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
      break;    
    case "long":
    case "int":
      $theValue = ($theValue != "") ? intval($theValue) : "NULL";
      break;
    case "double":
      $theValue = ($theValue != "") ? doubleval($theValue) : "NULL";
      break;
    case "date":
      $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
      break;
    case "defined":
      $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue;
      break;
  }
  return $theValue;
}
}

mysql_select_db($database_connect, $connect);
$query_Recordset1 = "SELECT *
FROM
creditebalance
GROUP BY
creditebalance.`name`
";
$Recordset1 = mysql_query($query_Recordset1, $connect) or die(mysql_error());
$row_Recordset1 = mysql_fetch_assoc($Recordset1);
$totalRows_Recordset1 = mysql_num_rows($Recordset1);
$mr = mysql_query("SET NAMES UTF8");
?>
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
</head>

<body>
<?php do { ?>
  <table width="228" border="1">
    <tr>
      <td width="163">Asian  online bill conclusion</td>
      <td width="7">&nbsp;</td>
      <td width="36">&nbsp;</td>
    </tr>
    <tr>
      <td><?php echo $row_Recordset1['name'];
	   $nameofbill = $row_Recordset1['name'];
$query_Recordset2 = "SELECT *
FROM
creditebalance
WHERE
creditebalance.name = $nameofbill


";	  

Open in new window

0
Comment
Question by:teera
2 Comments
 
LVL 109

Accepted Solution

by:
Ray Paseur earned 250 total points
ID: 39897193
I think we already talked about the MySQL extension, right?  I cannot imagine why you would still be posting code examples that use MySQL.

I'm going to recommend that you step back from this script and take some time to get a foundation in how PHP works.  From the look of this script, it appears that you're trying to learn PHP by copying Dreamweaver code.  And Dreamweaver has some of the worst PHP code ever written.  So just don't do that.  Instead, invest a couple of months of your life in learning the basics.   This article will get you started.
http://www.experts-exchange.com/Web_Development/Web_Languages-Standards/PHP/A_11769-And-by-the-way-I-am-new-to-PHP.html

In the instant case, the script has a parse error.  It also creates a query, but does not run the query.  It has SELECT * which is a code smell signaling "I don't know what I'm doing with SQL."  When there are anti-practices showing in the code, you can learn to avoid those by reading this article.
http://www.experts-exchange.com/Web_Development/Web_Languages-Standards/PHP/A_12293-AntiPHPatterns-and-AntiPHPractices.html

And (sigh) the script uses the MySQL extension.  That needs to change because PHP is doing away with MySQL support.  MySQL is already deprecated.  This article explains why and what you must do to keep your scripts running in the future.
http://www.experts-exchange.com/Web_Development/Web_Languages-Standards/PHP/PHP_Databases/A_11177-PHP-MySQL-Deprecated-as-of-PHP-5-5-0.html

Best regards, and best of luck with your project, ~Ray
0
 
LVL 12

Assisted Solution

by:North2Alaska
North2Alaska earned 250 total points
ID: 39897292
If creditebalance.name is a varchar then try this:

creditebalance.name = '$nameofbill'
0

Featured Post

Courses: Start Training Online With Pros, Today

Brush up on the basics or master the advanced techniques required to earn essential industry certifications, with Courses. Enroll in a course and start learning today. Training topics range from Android App Dev to the Xen Virtualization Platform.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

These days socially coordinated efforts have turned into a critical requirement for enterprises.
Password hashing is better than message digests or encryption, and you should be using it instead of message digests or encryption.  Find out why and how in this article, which supplements the original article on PHP Client Registration, Login, Logo…
Explain concepts important to validation of email addresses with regular expressions. Applies to most languages/tools that uses regular expressions. Consider email address RFCs: Look at HTML5 form input element (with type=email) regex pattern: T…
The viewer will learn how to look for a specific file type in a local or remote server directory using PHP.

776 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question