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duplicate error exception

Posted on 2014-03-03
Medium Priority
Last Modified: 2014-03-04

Let me know how to get rid of the duplication error while running the same data twice, how i can give a user friendly error

such " Duplication, please change the other data"

Exception in thread "main" org.springframework.dao.DuplicateKeyException: PreparedStatementCallback; SQL [INSERT INTO EMPLOYEE (ID, NAME, AGE) VALUES (?, ?, ?)]; Duplicate entry '223' for key 'PRIMARY'; nested exception is java.sql.BatchUpdateException: Duplicate entry '223' for key 'PRIMARY'
      at org.springframework.jdbc.support.SQLErrorCodeSQLExceptionTranslator.doTranslate(SQLErrorCodeSQLExceptionTranslator.java:245)
      at org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate(AbstractFallbackSQLExceptionTranslator.java:72)
      at org.springframework.jdbc.core.JdbcTemplate.execute(JdbcTemplate.java:605)
      at org.springframework.jdbc.core.JdbcTemplate.execute(JdbcTemplate.java:617)
      at org.springframework.jdbc.core.JdbcTemplate.batchUpdate(JdbcTemplate.java:890)
      at com.javacodegeeks.snippets.enterprise.dao.impl.JDBCEmployeeDAOImpl.insertBatch1(JDBCEmployeeDAOImpl.java:124)
      at com.javacodegeeks.snippets.enterprise.App.main(App.java:43)
Caused by: java.sql.BatchUpdateException: Duplicate entry '223' for key 'PRIMARY'
      at com.mysql.jdbc.PreparedStatement.executeBatchSerially(PreparedStatement.java:2056)
      at com.mysql.jdbc.PreparedStatement.executeBatch(PreparedStatement.java:1467)
      at org.springframework.jdbc.core.JdbcTemplate$4.doInPreparedStatement(JdbcTemplate.java:905)
      at org.springframework.jdbc.core.JdbcTemplate$4.doInPreparedStatement(JdbcTemplate.java:890)
      at org.springframework.jdbc.core.JdbcTemplate.execute(JdbcTemplate.java:589)
      ... 4 more

Here is the dao class

public class JDBCEmployeeDAOImpl implements JDBCEmployeeDAO{
	private DataSource dataSource;
	private JdbcTemplate jdbcTemplate;
	public void setDataSource(DataSource dataSource) {
		this.dataSource = dataSource;
	public void insert(Employee employee){
		String sql = "INSERT INTO employee " +
				                "(ID, NAME, AGE) VALUES (?, ?, ?)";
		Connection conn = null;
				        try {
					   conn = dataSource.getConnection();
				        PreparedStatement ps = conn.prepareStatement(sql);
					    ps.setInt(1, employee.getId());
			            ps.setString(2, employee.getName());
					    ps.setInt(3, employee.getAge());
					        } catch (SQLException e) {
				            throw new RuntimeException(e);
					        } finally {
					            if (conn != null) {
					                try {
					                } catch (SQLException e) {}
	@SuppressWarnings({ "unchecked", "rawtypes" })
	public Employee findById(int id){
		String sql = "SELECT * FROM EMPLOYEE WHERE ID = ?";

		jdbcTemplate = new JdbcTemplate(dataSource);
		Employee employee = (Employee) jdbcTemplate.queryForObject(
				sql, new Object[] { id }, new BeanPropertyRowMapper(Employee.class));
		return employee;

	public List<Employee> findAll(){
		jdbcTemplate = new JdbcTemplate(dataSource);
		String sql = "SELECT * FROM EMPLOYEE";
		List<Employee> employees = new ArrayList<Employee>();
		List<Map<String, Object>> rows = jdbcTemplate.queryForList(sql);
		for (Map row : rows) {
			Employee employee = new Employee();
		return employees;
	public String findNameById(int id){

		jdbcTemplate = new JdbcTemplate(dataSource);
		String name = (String)jdbcTemplate.queryForObject(
				sql, new Object[] { id }, String.class);
		return name;

	public void insertBatchSQL(final String sql){
		jdbcTemplate.batchUpdate(new String[]{sql});
	public void insertBatch1(final List<Employee> employees){

		jdbcTemplate = new JdbcTemplate(dataSource);
		  String sql = "INSERT INTO EMPLOYEE " +
			"(ID, NAME, AGE) VALUES (?, ?, ?)";
		  jdbcTemplate.batchUpdate(sql, new BatchPreparedStatementSetter() {
			public void setValues(PreparedStatement ps, int i) throws SQLException {
				Employee employee = employees.get(i);
				ps.setLong(1, employee.getId());
				ps.setString(2, employee.getName());
				ps.setInt(3, employee.getAge() );
			public int getBatchSize() {
				return employees.size();
	public void insertBatch2(final String sql){
		jdbcTemplate = new JdbcTemplate(dataSource); 
		jdbcTemplate.batchUpdate(new String[]{sql});

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here is the main method

public class App {

	@SuppressWarnings({ "rawtypes", "unchecked" })
	public static void main(String[] args) {
			ConfigurableApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");
	        JDBCEmployeeDAO jdbcEmployeeDAO = (JDBCEmployeeDAO) context.getBean("jdbcEmployeeDAO");

	        Employee emplNew1 = new Employee(23, "John", 23);
	        Employee emplNew2 = new Employee(223, "Mark", 43);
	        List<Employee> employeesN = new ArrayList();
	        System.out.println(" inserted rows: " + employeesN);

	        System.out.println(" FindAll : " + jdbcEmployeeDAO.findAll());
	        jdbcEmployeeDAO.insertBatch2("UPDATE EMPLOYEE SET NAME ='Mary'");
	        List<Employee> employees = jdbcEmployeeDAO.findAll();
	        System.out.println("Updated column name of table: " + employees);	
	        System.out.println(" FindAll : " + jdbcEmployeeDAO.findAll());

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Question by:roy_sanu
  • 4
  • 3
LVL 86

Expert Comment

ID: 39900321
change the other data
What do you mean by that actually? Changing any data other than the id (which i assume is the primary key) is not going to help.

Are you sure your use case is not to update the data?

Author Comment

ID: 39900508
idea; is i do not want error to be visible in the console need a customisation exception handler telling me" data is already available"

Author Comment

ID: 39900513
idea; is i do not want error to be visible in the console need a customisation exception handler telling me" data is already available"
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LVL 86

Expert Comment

ID: 39900837
Why would the user be looking at a console in the first place?

Author Comment

ID: 39900969
only thing i need is to select  if the id exist in the database... if that id exists, just display the "id exist with the database........ else insert into the database as new id...

let me know a piece of code how to check the validation on the current code base.....

LVL 86

Accepted Solution

CEHJ earned 2000 total points
ID: 39901022
else insert into the database as new id...
is more like it. Why then not just catch that org.springframework.dao.DuplicateKeyException? Having said that, it would be sounder programming just to issue a select on the id alone first

Author Closing Comment

ID: 39902868
Thank you Dear................

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