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Javascript: how do i check if node has children

Posted on 2014-03-03
5
246 Views
Last Modified: 2014-03-12
I have the following XML and I want a function that will throw an error whenever there's an instance of an Empty <Name> (or where <Name> has no children). How do I capture that?

<root>
	<Person>
		<Name/>
	</Person>
	<Person>
		<Name>
			<fname>babe</fname>
			<lname>ruth</lname>
		</Name>
	</Person>
</root>

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i have the following code:
var nsPerson = dom.SelectNode(dom.Root, "Person/Name");
if (nsPerson)
{
	for (var i=0; i < nsPerson.Count; i++)	
	{
		var nPerson =  nsPerson.GetItem(i);
		if (!nPerson)
		{
		  //throw "Empty Person.";
				
		}
	}
}

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0
Comment
Question by:badtz7229
  • 2
5 Comments
 
LVL 9

Expert Comment

by:Sar1973
ID: 39902678
With document.getElementById("yourItem").parentNode; see http://www.w3schools.com/jsref/prop_node_parentnode.asp.
0
 
LVL 52

Expert Comment

by:Scott Fell, EE MVE
ID: 39902685
Sar1973 how would you update his code using your solution?
0
 

Accepted Solution

by:
badtz7229 earned 0 total points
ID: 39913596
i answered my own question.

var nsPerson = dom.SelectNode(dom.Root, "Person/Name");
if (nsPerson)
{
      for (var i=0; i < nsPerson.Count; i++)      
      {
            var nPerson =  nsPerson.GetItem(i);
            if (nPerson)
            {
                           var hasChildren = nPerson.SelectSingle('*');
                           if (!hasChildren)
                                    throw "Empty, try again.";                  
                        
            }
      }
}
0
 

Author Closing Comment

by:badtz7229
ID: 39922903
this worked
0

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