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MySQL query output columns from rows

Posted on 2014-03-03
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Last Modified: 2014-03-04
I want to query a table called Vote_Record and output row data in columns, as follows:

Table: Vote_Record
+-------+---------+--------+
| Name	| Issue| Vote	|
+-------+---------+--------+
| Tom	| A	|  Yes	|
| Dick	| A	|  No	|
| Harry	| A	|  No	|
| Tom	| B	|  Yes	|
| Dick	| B	|  Yes	|
| Harry	| B	|  No	|
| Tom	| C	|  Yes	|
| Dick	| C	|  Yes	|
| Harry	| C	|  Yes	|
+-------+---------+--------+

Query Output
+---------+--------------+--------------+-------------+
| Name	| Issue A	| Issue B      | Issue C   |
+---------+--------------+--------------+-------------+
| Tom      | Yes        | Yes            | Yes           |
| Harry	| No         | No             | Yes          |
+---------+--------------+--------------+-------------+

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Sorry for the crazy table formatting -- I couldn't figure out how line up the columns...

Thanks!
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Question by:Ron1959
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5 Comments
 
LVL 17

Expert Comment

by:Kent Dyer
ID: 39902575
Baiscally, you are looking to do a PIVOT Query..

something like this..

select t3.name, t3.Issue_A, t3.Issue_B, t3.Issue_C  
from
(select t2.name as name, 
case when Issue_1 then "Yes"
else "No" end  Issue_A, 

case when Issue_2 then "Yes"
else "No" end Issue_B,

case when Issue_3 then 'Yes"
else "No" end Issue_C

from 
(SELECT partners.name as name, sales.products_id as prodid, count(products.name) as counts
FROM test.sales left outer join test.partners on sales.partners_id = partners.id
left outer join test.products on sales.products_id = products.id 
where sales.partners_id = partners.id and sales.products_id = products.id group by partners.name, prodid) t2) t3

group by t3.name ;

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0
 
LVL 58

Accepted Solution

by:
Julian Hansen earned 2000 total points
ID: 39902707
Assuming you have only 3 issue types then you can use the following query - if you have more then extend to match
SELECT `name`, 
	MAX(CASE WHEN issue='A' THEN vote END) IssueA, 
	MAX(CASE WHEN issue='B' THEN vote END) IssueB, 
	MAX(CASE WHEN issue='C' THEN vote END) IssueC
FROM `table`
GROUP BY `name`;

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0
 

Author Closing Comment

by:Ron1959
ID: 39903175
Wow, that's a very clean solution.  It should be easy to manage a large number of issues.

Please watch for my next question, which will have to do with "weighting" the votes and summing them for a total score.

Thanks!
0
 
LVL 58

Expert Comment

by:Julian Hansen
ID: 39903184
You are welcome - thanks for the points.
0
 
LVL 111

Expert Comment

by:Ray Paseur
ID: 39903201
Matrix inversion is a standard computer science problem, and there are many ways to do it.  This demonstrates the PHP logic.  

The essential moving parts look something like this (note the position of rows and columns in these two examples).

// CREATE THE EMPTY MATRIX OF COLUMNS (NAMES) AND ROWS (QUESTIONS)
$mat = array();
foreach ($cols as $c)
{
    foreach ($rows as $r)
    {
        $mat[$c][$r] = '-';
    }
}

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// CREATE THE EMPTY MATRIX OF COLUMNS (QUESTIONS) AND ROWS (NAMES)
$mat = array();
foreach ($rows as $r)
{
    foreach ($cols as $c)
    {
        $mat[$r][$c] = '-';
    }
}

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0

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