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SQL query help

Posted on 2014-03-03
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Last Modified: 2014-04-02
I have one table with two cols

Table1
-----------
col1                                                                  col2
-----                                                                  -----
",,"                  
(null)            
19/05/1975
27/08/1976
MK109 - Sales Training (All Staff)


What I want is to
1. update col2 with date format
2. If there is any data other than dd/mm/yyyy format (regex) make it to null

I used the below suggested

update source_trim set date_of_birth_1 = to_date(date_of_birth,'dd/mm/yyyy HH:MI AM')
where regexp_like(date_of_birth,'(0[1-9]|[12][0-9]|30|31)/(0[1-9]|1[12])/[0-9]{4}');

It updates the values for example 19/MAY/75, what i want is to append 12:00 AM as well. If its present in col1, i would use that, else I might simply append 12:00 AM.

How do i do that.
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Comment
Question by:Perumal_RM
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7 Comments
 
LVL 74

Expert Comment

by:sdstuber
ID: 39902496
since col2 is a date,  the 12:00am  or 00:00 is already part of the value.

There is nothing more to add.


Whenever a DATE value doesn't have time specified it always defaults to 00:00:00  (12am)
0
 
LVL 74

Expert Comment

by:sdstuber
ID: 39902502
If you're trying to see the time portion of your date then you need to format it into text

for example:


to_char(col2,'yyyy-mm-dd hh24:mi:ss')

or

to_char(col2,'dd/mm/yyyy hh:mi AM')
0
 

Author Comment

by:Perumal_RM
ID: 39902504
My col2 is varchar.

So its better i append those...
0
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LVL 143

Expert Comment

by:Guy Hengel [angelIII / a3]
ID: 39902598
posting my comment from your duplicate question:
http://www.experts-exchange.com/Programming/Languages/SQL_Syntax/Q_28379519.html

udpate yourtable 
  set col2 = case when col1 like '[0-3][0-9]/[0-1][0-9]/[0-9][0-9][0-9][0-9]% 
then replace(col1 , ' at ', ' ' )
else null end  

Open in new window

0
 

Author Comment

by:Perumal_RM
ID: 39905009
Didnt worked. Pasting my original query here

update source_trim
set last_action_date_1 = case when last_action_date like '[0-3][0-9]/[0-1][0-9]/[0-9][0-9][0-9][0-9]%
then replace(last_action_date,' at ',' ')
else null end;

Error starting at line 3 in command:
update source_trim  
set last_action_date_1 = case when last_action_date like '[0-3][0-9]/[0-1][0-9]/[0-9][0-9][0-9][0-9]%  
then replace(last_action_date,' at ',' ')
else null end;
Error at Command Line:5 Column:32
Error report:
SQL Error: ORA-00905: missing keyword
00905. 00000 -  "missing keyword"
*Cause:    
*Action:
0
 

Author Comment

by:Perumal_RM
ID: 39905201
update source_trim
set last_action_date_1=replace(last_action_date,' at ',' ');

I used this and it worked...
0
 
LVL 143

Accepted Solution

by:
Guy Hengel [angelIII / a3] earned 2000 total points
ID: 39906593
sorry, a closing quote was missing:
update source_trim
set last_action_date_1 = case when last_action_date like '[0-3][0-9]/[0-1][0-9]/[0-9][0-9][0-9][0-9]%'
then replace(last_action_date,' at ',' ')
else null end;

Open in new window

0

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