Removing ASC 63 character from Excel - TRIM, CLEAN and SUBSTITUTE not working...

Hello Experts

I'm trying to remove some extra white spaces, but TRIM, CLEAN and SUBSTITUTE not working.

I used CODE( ) to identify the character as 63. I tried to use SUBSTITUTE but it didn't work.

I'm stumped!

Source text is Japanese.

Please see attached workbook for a few examples.
tomfolinsbeeAsked:
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tel2Commented:
Hi Tom,

ASCII 63 is "?", so...

With Excel 2003, if I put this in A1:
    1?2?3
then this in A2:
    =SUBSTITUTE(A1,"?","")
then this appears in A2:
    123

To start with, please try exactly that, and let us know the results.
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zorvek (Kevin Jones)ConsultantCommented:
If the original text is Japanese then it's double byte or unicode text. I'm puzzled how you are identifying "white space" as a 63 which, as tel2 pointed out, is a ASCII question mark.

Can you post the workbook? You said you did but it was not posted in the question.

Kevin
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tomfolinsbeeAuthor Commented:
Thanks for the replies.

Here's the file with some samples.

The white space is in the last position. This expression returns 63...

=CODE(RIGHT(A2,1))

Thanks!
extra-white-space.xlsx
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zorvek (Kevin Jones)ConsultantCommented:
The problem is that you are working with double byte or unicode text. The CODE function only works with ASCII (single byte) text so it is only picking up part of the two byte character.

The only way I can think of doing this is to use functions that handle unicode text and put a copy of the "white space" double byte character in a special cell so we can use it.

This formula works:

=SUBSTITUTE(A2,O$1,"")

assuming you have a copy of the "white space" character in O1.

See the attached workbook.

Kevin
extra-white-space.xlsx
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tomfolinsbeeAuthor Commented:
Thanks, that did the trick.
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