Improve company productivity with a Business Account.Sign Up

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 497
  • Last Modified:

capture data for the week

Hello experts,

I need to help with the following syntax.  I need to capture sales for the current and sales for the same week last year.

Current calender  week: ?

Current calender   week Last year: ?
0
tips54
Asked:
tips54
  • 7
  • 6
1 Solution
 
ravikantninaveCommented:
find current calendar week
select DATEPART(WEEK,GETDATE())
0
 
ravikantninaveCommented:
Here is full solution:

DECLARE @datecol datetime = GETDATE();
DECLARE @WeekNum INT
      , @YearNum char(4);

SELECT @WeekNum = DATEPART(WK, @datecol)
     , @YearNum = CAST(DATEPART(YY, @datecol) AS CHAR(4));

-- once you have the @WeekNum and @YearNum set, the following calculates the date range.
SELECT DATEADD(wk, DATEDIFF(wk, 6, '1/1/' + @YearNum) + (@WeekNum-1), 6) AS StartOfWeek;
SELECT DATEADD(wk, DATEDIFF(wk, 5, '1/1/' + @YearNum) + (@WeekNum-1), 5) AS EndOfWeek;

--
Declare @NextDate datetime= DATEADD(YEAR,-1, getdate())
SET @YearNum= CAST(DATEPART(YY, @NextDate) AS CHAR(4));
SELECT DATEADD(wk, DATEDIFF(wk, 6, '1/1/' + @YearNum) + (@WeekNum-1), 6) AS StartOfWeek;
SELECT DATEADD(wk, DATEDIFF(wk, 5, '1/1/' + @YearNum) + (@WeekNum-1), 5) AS EndOfWeek;
0
 
tips54Author Commented:
Hi Ravi,
 
Your code returns the current week number for the year. (10)

what I'm after is something that returns : 3/2/2014 - 3/8/2014

And 3/2/2013  -  3/8/2013
0
What Kind of Coding Program is Right for You?

There are many ways to learn to code these days. From coding bootcamps like Flatiron School to online courses to totally free beginner resources. The best way to learn to code depends on many factors, but the most important one is you. See what course is best for you.

 
ravikantninaveCommented:
3/2/2014 - 3/8/2014 is the date range of current year of the 10 th week.

and date of 10th week of last year was 3/2/2013  -  3/8/2013
0
 
tips54Author Commented:
If I have a table with multiple invoices with dates,  how would the syntax look for sum of invoices for just week 10?
0
 
ravikantninaveCommented:
DECLARE @FirstDate as datetime = DATEADD(wk, DATEDIFF(wk, 6, '1/1/' + @YearNum) + (@WeekNum-1), 6) --AS StartOfWeek;
DECLARE @SecondDate as datetime = DATEADD(wk, DATEDIFF(wk, 5, '1/1/' + @YearNum) + (@WeekNum-1), 5) --AS EndOfWeek;

Select sum(Amount) from Invoices Where InvDate > = @FirstDate and InvDate <=@SecondDate
0
 
ravikantninaveCommented:
Same for last year
Declare @ThirdDate as datetime =DATEADD(wk, DATEDIFF(wk, 6, '1/1/' + @YearNum) + (@WeekNum-1), 6) --AS StartOfWeek;
Declare @ForthDate as Datetime =DATEADD(wk, DATEDIFF(wk, 5, '1/1/' + @YearNum) + (@WeekNum-1), 5) --AS EndOfWeek;

Select sum(Amount) from Invoices Where InvDate > = @ThirdDate and InvDate <=@ForthDate
0
 
tips54Author Commented:
where does it differentiate Current and Last year?

I get this error when I run the code:  
Cannot assign a default value to a local variable.
0
 
tips54Author Commented:
Thanks ravikantninave,

I got it.  I had to set those values on the next line. This might be a Sql 2005 issue.
Thanks again.

What I Used:

/*
DECLARE @datecol datetime
set @datecol = GETDATE();
DECLARE @WeekNum INT
set @WeekNum = DATEPART(week,GETDATE());
   DECLARE    @YearNum char(4);
set @YearNum =DATEPART(year,GETDATE());

Declare @NextDate datetime
SET @NextDate= DATEADD(YEAR,-1, getdate())
DECLARE    @YearNum2 char(4);
SET @YearNum2= CAST(DATEPART(YY, @NextDate) AS CHAR(4));

-- once you have the @WeekNum and @YearNum set, the following calculates the date range.
SELECT DATEADD(wk, DATEDIFF(wk, 6, '1/1/' + @YearNum) + (@WeekNum-1), 6) AS StartOfWeek;
SELECT DATEADD(wk, DATEDIFF(wk, 5, '1/1/' + @YearNum) + (@WeekNum-1), 5) AS EndOfWeek;

SELECT DATEADD(wk, DATEDIFF(wk, 6, '1/1/' + @YearNum2) + (@WeekNum-1), 6) AS StartOfWeek;
SELECT DATEADD(wk, DATEDIFF(wk, 5, '1/1/' + @YearNum2) + (@WeekNum-1), 5) AS EndOfWeek;

*/
0
 
tips54Author Commented:
How would I get the sum for the quarter?
0
 
tips54Author Commented:
I would like to capture the same data quarterly compare to last years quarter.
0
 
ravikantninaveCommented:
first three months of the year? or what? Find quarter :

SELECT DATEADD(mm, (quarter - 1) * 3, year_date) StartDate,
       DATEADD(dd, -1, DATEADD(mm, quarter * 3, year_date)) EndDate,
       quarter QuarterNo
  FROM
(
  SELECT '2013-01-01' year_date
) s CROSS JOIN
(
  SELECT 1 quarter UNION ALL
  SELECT 2 UNION ALL
  SELECT 3 UNION ALL
  SELECT 4
) q
0
 
tips54Author Commented:
Thank you.

the second question was answered here:
http://www.experts-exchange.com/Database/MS-SQL-Server/Q_28381957.html
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

Join & Write a Comment

Featured Post

A proven path to a career in data science

At Springboard, we know how to get you a job in data science. With Springboard’s Data Science Career Track, you’ll master data science  with a curriculum built by industry experts. You’ll work on real projects, and get 1-on-1 mentorship from a data scientist.

  • 7
  • 6
Tackle projects and never again get stuck behind a technical roadblock.
Join Now