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SQL Syntax

I'm trying to understand someone else's syntax: -

These are the parameters: -
      DECLARE @TodayStart AS DATETIME, @TodayEnd AS DATETIME
      SET @TodayStart = DATEADD(dd, DATEDIFF(dd,0,getdate()), 0)
      SET @TodayEnd = DATEADD(dd, 1, @TodayStart)

This is the 'where' part of the query: -
      WHERE [ReceiptDate] >= '''+@TodayStart+'''
      AND [ReceiptDate] < '''+@TodayEnd+'''

Can anyone tell me what date range will be returned by this query?
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HKFuey
Asked:
HKFuey
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1 Solution
 
Geert GruwezOracle dbaCommented:
lol ... i guess this are the same 2 lines
SET @TodayStart = DATEADD(dd, DATEDIFF(dd,0,getdate()), 0)

SET @TodayStart = getdate()


daterange is from today until tomorrow
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HKFueyAuthor Commented:
So, even though it is convoluted, the results will be transactions from 'Today'?
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Harish VargheseProject LeaderCommented:
Hello,

SET @TodayStart = DATEADD(dd, DATEDIFF(dd,0,getdate()), 0)

This statement sets @TodayStart as beginning time of today, like '2014/03/06 00:00:00'
Below statement adds one day to @TodayStart which will set @TodayEnd to beginning time of tomorrow, like '0314/03/07 00:00:00'
SET @TodayEnd = DATEADD(dd, 1, @TodayStart)

And below final clause will return all records with ReceiptDate falling any time today. This is required only when you have time part in ReceiptDate column:
WHERE [ReceiptDate] >= '''+@TodayStart+'''
      AND [ReceiptDate] < '''+@TodayEnd+'''


-Harish
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HKFueyAuthor Commented:
That's very clear, thanks very much!
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Harish VargheseProject LeaderCommented:
You can also replace   SET @TodayStart = DATEADD(dd, DATEDIFF(dd,0,getdate()), 0)
with   SET @TodayStart = convert(varchar, getdate(), 111), which is just trimming the time part from datetime value.
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