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Shell - Command to count lines per hour (Solaris 10)

Posted on 2014-03-10
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Last Modified: 2014-03-17
Hi,

I have a log file which has the following line repeated several times during a day:

2014-03-10 00:00:35.970 [80] Debug      HttpReceiverServlet            Incoming request url : http://10.129.65.23:7920/httpeventadapter/SP_ADD/httpAdapter/ST.TERMINAL_SWITCH query string ST.MSISDN=5567
.
.
2014-03-10 00:00:36.075 [80] Debug      HttpReceiverServlet            Incoming request url : http://10.129.65.23:7920/httpeventadapter/SP_ADD/httpAdapter/ST.TERMINAL_SWITCH query string ST.MSISDN=55494
.
.


So what I need to have an output of how many times does this line appears in the period of an hour...

Pls note that the line has in common the beggining of it.. the rest differs... so what I need is a sort of grep "Incoming request url" | wc -l and in the output something like this:

00:00  10000  <---- (number of times that the "Incoming request url"  appeared from 00:01 to 00:59)
.
04:00   20000
.
.
15:00   2000
16:00   4000

Until 23:00... is this possible to be done?

Im on Solaris 10.

Tks,
Joao
0
Comment
Question by:joaotelles
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8 Comments
 
LVL 40

Expert Comment

by:omarfarid
ID: 39917893
try this

awk '{ print $2 }' filename | awk -F":" '{ print $1 }' | sort | uniq -c
0
 

Author Comment

by:joaotelles
ID: 39918058
I got the wrong output...

awk '{ print $2 }' filename | awk -F":" '{ print $1 }' | sort | uniq -c
   2 EventId=2696257,
   2 EventId=2696259,
   2 EventId=2696265,
   2 EventId=2696268,
   2 EventId=2696271,
   2 EventId=2696274,

I grepped the "EventId=2696257" and saw that you got the wrong line..

2014-03-10 01:12:05.483 [344] Flow       HttpNotificationClient         Sending notification RequestHolder [Notification name=TerminalSwitch_3G_To_2G, URL=ht
tp://mdm2a:7920/air-integration/not,  Method=POST, ContentType=text/xml, Url parameters=?ST.MSISDN=556193350627,
Body=<methodCall><methodName>UpdateSubscriberSegmentation</methodName><params><param><value><struct><member><name>originNodeType</name><value>EXT</value></me
mber><member><name>originHostName</name><value>MDM</value></member><member><name>originTransactionID</name><value>58748988436</value></member><member><name>o
riginTimeStamp</name><value><dateTime.iso8601>20140310T01:11:56-0300</dateTime.iso8601></value></member><member><name>subscriberNumber</name><value>556193350
627</value></member><member><name>originOperatorID</name><value>MDM</value></member><member><name>serviceOfferings</name><value><array><data><value><struct><
member><name>serviceOfferingID</name><value><int>26</int></value></member><member><name>serviceOfferingActiveFlag</name><value><boolean>1</boolean></value></
member></struct></value><value><struct><member><name>serviceOfferingID</name><value><int>27</int></value></member><member><name>serviceOfferingActiveFlag</na
me><value><boolean>0</boolean></value></member></struct></value></data></array></value></member></struct></value></param></params></methodCall>
, EventId=2696257, Time=20140310T01:11:56-0300]

========================
0
 
LVL 68

Accepted Solution

by:
woolmilkporc earned 500 total points
ID: 39918078
I think you should take the date into account, in case the log file would span several days.

Try this:
nawk -F: '/Incoming request url/ {A[$1]+=1} END {for (n in A) print n, "->", A[n]}' log.txt | sort

Open in new window

If you really want to ignore the date:
nawk -F":| " '/Incoming request url/ {A[$2]+=1} END {for (n in A) print n, "->", A[n]}' log.txt | sort

Open in new window

Please note that using "nawk" instead of "awk" for this latter version is important under Solaris!
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LVL 29

Expert Comment

by:MikeOM_DBA
ID: 39918768
Perhaps this will help:
awk -F'[ :]' '/Incoming request url/{
  dt=$1" "$2; 
  if(k==dt){c+=1}
  else { if(c>0){print k" -> "c;}
  c=1;k=dt}
} END {print k" -> "c}' log.txt

Open in new window

0
 
LVL 2

Expert Comment

by:c_kedar
ID: 39920302
I guess this simple one liner will do, unless I am missing some point
cut -d : -f 1,2 filename | sort | uniq -c

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You can omit 'sort' if it is safe to assume that in log file time will always be ascending.
0
 
LVL 29

Expert Comment

by:MikeOM_DBA
ID: 39920529
@c_kedar, Unfortunalely the one - liner does not count the 'number of times that the "Incoming request url"  appeared'
:p
0
 
LVL 2

Expert Comment

by:c_kedar
ID: 39921407
I missed that requirement. It is simple to add, though:
grep "Incoming request url"  filename | cut -d : -f 1,2 | sort | uniq -c

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0
 

Author Closing Comment

by:joaotelles
ID: 39933994
Tks.
0

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