asked on

Outputting timesheet totals

Here is the table:

tracking_id, project_id, project_time, createdat

1,1,2.5,2014-03-10
2,1,3.5,2014-03-11
3,1,4.5,2014-03-12
4,1,5.5,2014-03-13
5,1,2.5,2014-03-14
6,2,3.5,2014-03-10
7,2,3.5,2014-03-11
8,2,3.5,2014-03-12
9,2,4.5,2014-03-13
10,2,4.5,2014-03-14

Title Line of Report

Totals for 8/10 - 8/14

Project ID | Mon | Tue | Wed | Thu | Fri

Where the day columns are the total from the database for that day for the project

1. Some days might be missing.
2. the date range is dynamic.

Here is what I have so far:

http://sqlfiddle.com/#!2/69e8f0/3

The query returns the results but not in a way I can easily generate an html table.

What I need to know: is their an easy way to rewrite the query so that there is 1 row per project_id and all the totals returned...

or how would I go about writing the PHP to output 1 row per project_id and the totals for the day columns.

Attached is a sample report, but it does not correlate with the data in the fiddle.
sample-report.PNG

gplana

Not sure if I understand your question, but I think this code is what you need (supposing you already have the connection made to mysql):

<table>
<?php
$strSQL = 'SELECT
	project_id,
	FROM_DAYS(TO_DAYS(createdat)) AS createdat,
	sum(project_time) AS project_time
FROM
	tracking
WHERE
	createdat >= \'2014-03-08\'
AND createdat <= \'2014-03-15\'
GROUP BY
	project_id,
	FROM_DAYS(TO_DAYS(createdat))';

$query = mysql_query($strSQL);
for ($i=0; $i<mysql_num_rows($query): $i++){
   $tracking_id = mysql_result($query,$i,0);
   $project_id = mysql_result($query,$i,1);
   $project_time = mysql_result($query,$i,2);
   $createdat = mysql_result($query,$i,3);
?>
<tr>
<td><?php echo $tracking_id; ?></td>
<td><?php echo $project_id; ?></td>
<td><?php echo $project_time; ?></td>
<td><?php echo $createdat; ?></td>
</tr>
<?php
   } // end of for
?>
</table>

Open in new window

Hope it helps. Regards.

Randy Johnson

ASKER

Sorry for not better explaining myself.

The issue I had and your code has is if there are 5 entries in the table for a project id, there will be 5 rows in the output report and that is not what I want.

This might make it easier:

I want 1 row per project_id in the output report.

I want the totals for the particular date.

For project one I want the total hours for 3/10/2014 to be in the Monday column, the total hours for 3/11/2014 to be in the Tuesday column etc.

ASKER CERTIFIED SOLUTION

Randy Johnson

membership

This solution is only available to members.

To access this solution, you must be a member of Experts Exchange.

Start Free Trial

gplana

Oh, sorry, I didn't understood.

I think you should just remove last line on the group by so only the project id is on your group by clause.

So change this:

$strSQL = 'SELECT
	project_id,
	FROM_DAYS(TO_DAYS(createdat)) AS createdat,
	sum(project_time) AS project_time
FROM
	tracking
WHERE
	createdat >= \'2014-03-08\'
AND createdat <= \'2014-03-15\'
GROUP BY
	project_id,
	FROM_DAYS(TO_DAYS(createdat))';

Open in new window

to this:

$strSQL = 'SELECT
	project_id,
	FROM_DAYS(TO_DAYS(AVG(createdat))) AS createdat,
	sum(project_time) AS project_time
FROM
	tracking
WHERE
	createdat >= \'2014-03-08\'
AND createdat <= \'2014-03-15\'
GROUP BY
	project_id;

Open in new window

and let me know if this works.

Randy Johnson

ASKER

if you do that then only 1 date is returned instead of all dates

gplana

Yes, but isn't this what you want? Don't you sant just one record by project?

Randy Johnson

ASKER

I want 1 project_id row but the totals for each date

gplana

Not sure if I understand. If you have these rows:

Project date
1 Today
1 Tomorrow
2 Today
2 Tomorrow

Which rows do you want to be on the resultset?

Randy Johnson

ASKER

The 2 dimensional array was the key as explained in my post. Thanks to those that tried to help