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Cutting up a base file into x parts

Posted on 2014-03-15
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Last Modified: 2014-03-16
Hi,

   I have a base file of approx. 300K records. I want to write a batch file that can cut up this file into x portions in sequential order. The x is provided as a input parameter to the batch. We can name the output files as batch<1-x>.txt

Sample base file contains the following contents:
"\\server1\file1"
''\\Server2\file2"
etc

How do I do this?
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Question by:LuckyLucks
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Accepted Solution

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oBdA earned 2000 total points
ID: 39931621
Try it with this:
@echo off
setlocal enabledelayedexpansion
REM Source file to break down:
set SourceFile=D:\Temp\base.txt
REM File names to create; "-<Index>.<Extension>" will be added automatically
set TargetBaseName=D:\Temp\batch
for %%a in ("%SourceFile%") do set TargetExt=%%~xa
if "%~1"=="" (
	set TotalFiles=
	set /p TotalFiles=Enter the number of files to create from '%SourceFile%': 
) else (
	set TotalFiles=%~1
)
if "%TotalFiles%"=="" goto :eof
for /f "delims=" %%a in ('find.exe /c /v "" "%SourceFile%"') do set Find=%%a
for %%a in (%Find%) do set TotalLines=%%a
echo Total lines to process: %TotalLines%
set /a BreakCount = TotalLines / TotalFiles
set /a Remainder = TotalLines %% TotalFiles
if %Remainder% neq 0 set /a BreakCount += 1
echo Number of lines in each file: %BreakCount%
echo Processing ...
set /a LineCount = 0
set /a FileCount = 1
echo [!FileCount!/!TotalFiles!] "%TargetBaseName%-!FileCount!%TargetExt%"
if exist "%TargetBaseName%-!FileCount!%TargetExt%" del "%TargetBaseName%-!FileCount!%TargetExt%"
for /f "usebackq delims=" %%a in ("%SourceFile%") do (
	set /a LineCount += 1
	>>"%TargetBaseName%-!FileCount!%TargetExt%" echo %%a
	if !LineCount! geq %BreakCount% (
		set /a LineCount = 0
		set /a FileCount += 1
		if exist "%TargetBaseName%-!FileCount!%TargetExt%" del "%TargetBaseName%-!FileCount!%TargetExt%"
		echo [!FileCount!/!TotalFiles!] "%TargetBaseName%-!FileCount!%TargetExt%"
	)
)
echo Done.

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